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Pavlova-9 [17]
3 years ago
5

If the distance traveled is 14.25m, what is the average velocity?

Mathematics
1 answer:
babymother [125]3 years ago
3 0
60 mile per hour in the car i think
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Using Ratios to Solve Problems - Item 1457 Question 4 of 7 Evan's family drove to a theme park for vacation. They drove the same
azamat

Answer:

150 miles

distance travelled on the third day = 150 miles

Step-by-step explanation:

Note: it was given that they drove the same speed throughout the trip. That means their speed is constant for all days;

For the first day

distance = 300 miles

time = 6 hours

Speed = distance/time

Speed = 300/6 = 50 mph

on the third day;

time = 3 hours

Speed = speed on first day = 50 mph

distance = speed × time

distance = 50 mph × 3 hours

distance = 150 miles

distance travelled on the third day = 150 miles

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3 years ago
-1/2 + ( 3/4 x 4/9)
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Answer:

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Step-by-step explanation:

-1/2 + ( 3/4 x 4/9)

PEMDAS says parentheses first

Rearranging the fractions

-1/2 + ( 3/9 x 4/4)

-1/2 + (1/3*1)

-1/2 + 1/3

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Write a decimal where the value of a digit is one tenth as much as a digit in another place
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Write the equation of a Line that is perpendicular to y=5/2x+3 and passes
koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\

        m_{2}= -1 ÷ m_{1}

               = -1*\frac{2}{5}=\frac{-2}{5}

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

                                                y - [5] = \frac{-2}{5}(x - [-3])\\

                                               y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\   y =\frac{-2}{5}x-\frac{6}{5}-5\\\\   y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}

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3 years ago
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