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JulijaS [17]
3 years ago
9

A circle with area \blue{25\pi}25πstart color #6495ed, 25, pi, end color #6495ed has a sector with a central angle of \purple{\d

frac{9}{10}\pi} 10 9 ​ πstart color #9d38bd, start fraction, 9, divided by, 10, end fraction, pi, end color #9d38bd radians .
Mathematics
1 answer:
vredina [299]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that

The area of circle is 25π square unit

Area = 25π square unit

The area of a circle can be calculated using

Area = πr²

Where r is radius of the circle

Then, let find the radius of the circle

Area = πr²

25π = πr²

Divided Both side by π

25π / π = πr² / π

25 = r²

Take square root of both sides

√25 = √r²

5 = r

Then, the radius of the circle is 5 unit

Then, given that the angle subtended by the sector is 9π/10 rad

θ = 9π/10 rad

Then, we want to find the area of the sector

Area of a sector is calculated using

Area of sector = (θ / 360) × πr²

Area of sector = θ × πr² / 360

The formula is in degree let convert to radian

360° = 2π rad.

Then,

Area of sector = θ × πr² / 2π rad

Then,

Area of sector = θ × r² / 2

Area of sector = ½ θ•r²

Then, Area of the sector is

A = ½ θ•r²

A = ½ × (9π / 10) × 5²

A = (9π × 5²) / (2 × 10)

A = 225π / 20

A = 45π / 4

A = 11.25π Square unit

A = 35.34 square unit

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A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec
Paraphin [41]

Answer:

A. The solutions are x=3i,\:x=-3i.

B. The factored form of the quadratic expression x^2+9=(x-3i)(x+3i)

Step-by-step explanation:

A. To find the solutions to the quadratic equation x^2+9=0 you must:

\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}

x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i

The solutions are:

x=3i,\:x=-3i

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor x^2+9:

First, multiply the constant in the polynomial by i^2 where i^2 is equal to -1.

x^2+9i^2

Since both terms are perfect squares, factor using the difference of squares formula

a^2-i^2=(a+i)(a-i)

x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)

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