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JulijaS [17]
3 years ago
9

A circle with area \blue{25\pi}25πstart color #6495ed, 25, pi, end color #6495ed has a sector with a central angle of \purple{\d

frac{9}{10}\pi} 10 9 ​ πstart color #9d38bd, start fraction, 9, divided by, 10, end fraction, pi, end color #9d38bd radians .
Mathematics
1 answer:
vredina [299]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that

The area of circle is 25π square unit

Area = 25π square unit

The area of a circle can be calculated using

Area = πr²

Where r is radius of the circle

Then, let find the radius of the circle

Area = πr²

25π = πr²

Divided Both side by π

25π / π = πr² / π

25 = r²

Take square root of both sides

√25 = √r²

5 = r

Then, the radius of the circle is 5 unit

Then, given that the angle subtended by the sector is 9π/10 rad

θ = 9π/10 rad

Then, we want to find the area of the sector

Area of a sector is calculated using

Area of sector = (θ / 360) × πr²

Area of sector = θ × πr² / 360

The formula is in degree let convert to radian

360° = 2π rad.

Then,

Area of sector = θ × πr² / 2π rad

Then,

Area of sector = θ × r² / 2

Area of sector = ½ θ•r²

Then, Area of the sector is

A = ½ θ•r²

A = ½ × (9π / 10) × 5²

A = (9π × 5²) / (2 × 10)

A = 225π / 20

A = 45π / 4

A = 11.25π Square unit

A = 35.34 square unit

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I. Tell whether each statement is TRUE or FALSE. Refer to the figure below. Write your answer on the space provided.
Vika [28.1K]

Answer:

1. TRUE

2. TRUE

3. TRUE

4. TRUE

5. FALSE

6. TRUE

Step-by-step explanation:

1. From the diagram, we have that m∠2 and m∠7 are alternate interior angles

If m∠2 = 70° and m∠7 = 70°, then we have;

m∠2 = 70° = m∠7

m∠2 = m∠7

Therefore, the alternate interior angles of the lines l₁, and l₂ are equal, and therefore, the lines l₁ and l₂ are parallel, l₁ ║ l₂

TRUE

2. If m∠3 = 90° and m∠7 = 90°, therefore, the angle formed by the intersection of l₃ and l₂ = 90°

Therefore l₃ ⊥ l₂

TRUE

3. m∠5 and m∠7 are corresponding angles

If m∠5 = 85° and m∠7 = 85°, then, m∠5 = m∠7

Therefore, the corresponding angles formed by the lines l₁ and l₂ are equal, therefore;

l₁ ║ l₂

TRUE

4. Whereby we have, m∠1 = m∠5, we get;

m∠1 + m∠5 = 180° by sum of angles on a straight line

∴ m∠1 + m∠5 = m∠1 + m∠1 = 2·m∠1 = 180°

m∠1 = 180°/2 = 90°

∴ m∠1 = 90° = m∠5, and l₃ ⊥ l₁

TRUE

5. m∠1 and m∠8 are alternate exterior angles

If m∠1 = 98° and m∠8 = 82°

∴ m∠1 ≠ m∠8 and l₁ ∦ l₈

FALSE

6. Given that l₁║ l₂, then the angle formed between l₁ and l₃ will be equal to th angle formed between l₂ and l₃

Therefore;

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3 years ago
Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2
soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

<u>Solution:</u>

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is \frac{-1}{2}

Need to determine value of r.

Slope of a line passing through point \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)  is given by following formula:

\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}  --- eqn 1

\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}

On substituting the given value in (1) we get

\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}

Hence the value of "r" is -2

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