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Hunter-Best [27]
3 years ago
7

Please answer this the best you possible can :)

Mathematics
2 answers:
Veronika [31]3 years ago
7 0

Answer:

the answer is x=15

Step-by-step explanation:

75/5=15

120/8=15

180/12=15

Hope this helps some.

In-s [12.5K]3 years ago
5 0

Answer:

the answer is 15

Step-by-step explanation:

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Is this wrong?
sammy [17]

Step-by-step explanation:

The last step is a little wrong. Lemme show you:

x(x + 2) + (x + 2)

Imagine there is an invisible '1' infront of (x + 2) like this:

= x(x + 2) + 1(x + 2)

Now we can combine the like terms together:

= (x + 1)(x + 2)

This is the correct factorization.

4 0
3 years ago
I'll give you more points but you have to answer all the parts to the question. I need this plsssss ty lol. Show all work too pl
alexira [117]

Answer:

a) 34mi

b) 10mi

c) 44mi

d) by Calculating the amount of miles it would take John to go to school plus the amount of miles it would take Sara to go to school. Then add the sum of the amount of miles it took for both to go to school.

Step-by-step explanation:

a) explanation:

a^{2} +b^2=c^2

16^2+30^2=c^2

256 + 900 = c^2

c^2=1156

\sqrt{1156}=34mi

b) explanation:

a^{2} +b^2=c^2

6^2+8^2=c^2

36+64=c^2

c^2=100

\sqrt{100} =10mi

c) explanation: we already have all the data from John's house to Sara's House.

John's House to Sara's House = John's House to School + Sara's House to School.

Sara's House to School (Question #1) = 34mi

John's House to School (Question #2) = 10mi

34(mi) + 10(mi) = 44(mi)

d) explanation: explanation is on the answer

7 0
3 years ago
The new ointment was applied to four locations, and a control was applied to the other four. How many different choices were the
lubasha [3.4K]

Answer:

there are 70 possible choices for the four locations to apply the new ointment

Step-by-step explanation:

Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

therefore

number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations

thus there are 70 possible choices for the four locations to apply the new ointment

6 0
3 years ago
See image for question.​
kotegsom [21]

Answer:

<h3>#7</h3>

(a)

<u>Sample space:</u>

  • 1*1, 1*2, 1*3, 1*4,
  • 2*1, 2*2, 2*3, 2*4,
  • 3*1, 3*2, 3*3, 3*4,
  • 4*1, 4*2, 4*3, 4*4

Total 16 outcomes

(b)

  • (i) P(even) = 12/16 = 3/4
  • (ii) P(3x) = 7/16
  • (iii) P(perfect square) = 4/16 = 1/4
<h3>#8</h3>

(a) <u>Sample space:</u>

  • 1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

  • P(T and odd) = 2/8 = 1/4

(ii) 1H, 4H

  • P(H and square) = 2/8 = 1/4

(iii) 1H, 2H, 3H, 4H

  • P(H) = 4/8 = 1/2

6 0
3 years ago
Solve for d when 2x-2yd=y+xd ...?
11Alexandr11 [23.1K]
2x-2yd=y+xd 2x-y=xd+2yd 2x-y=d(x+2y) (2x-y)/(x+2y)=d So the answer is <span><span>d=<span><span>2x−y</span><span>x+2y</span></span></span></span>
3 0
3 years ago
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