18 + 81 = 9(x²<span> + 6x + 9)
</span><span>11 = (x + 3)</span>²
When we are completing the square, we are going to move the value of c across the equals. We will do that by adding, and end up with
18=9(x²+6x)
We take the value of b (the coefficient of x), divide it by 2 and square it:
(6/2)²=3²=9
This is the value that completes the square. However, since the entire square is multiplied by 9, this value must be multiplied by 9 before we can add it across the equals:
18+9(9) = 9(x²+6x+9)
18+81=9(x²+6x+9)
99=9(x²+6x+9)
Dividing both sides by 9, we have:
11=x²+6x+9
11=(x+3)²
Hello.
C) x=4π/3
The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).
Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.
Have a nice day
You cannot simplify this but you can factorise it:
9x^6 (x^2 - 2)
Answer:
the answer is B
Step-by-step explanation:
$8 per day
$6 per walk
walk(w)
8+6w
