Answer:
g^-1(x)= -(x/3) - 6
Step-by-step explanation:
Answer:
let be x and multiple 3 both and 8 both
The answer to a "sum and difference" problem is that the larger number is the average of those given: (43 +15)/2 = 29.
The smaller number can be computed any of several ways, but subtracting the difference works: 29 -15 = 14
The larger number is 29.
The smaller number is 14.
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You can let the numbers be a and b, and let the sum and difference be s and d. Then you have
.. a + b = s
.. a - b = d
Add these two equations, and you find "b" is eliminated:
.. 2a = s + d
.. a = (s + d)/2 . . . . . . the average of the sum and difference
.. b = a - d . . . . . . . . . from the second equation
This solution is generic. Even if you have to "show work" on such a problem, you can use this known result to check your work.
The smaller of 2 consecutive integers is -15. The equation to determine the consecutive integers is x + (x + 1) = -29
<u>Solution:</u>
Given that sum of two consecutive integer is -29.
Need to write the equation and determine the smaller of 2 consecutive integers.
Let’s smaller integer be represented by variable x
So bigger consecutive integer will be represented by x + 1
As sum of two integer = -29
=> x + (x + 1) = -29
=> 2x + 1 = -29
=> 2x + 30 = 0 ----------(1)
On solving equation (1) for x we get
2x =-30
=> x = -15
Smallest integer = x = -15
Bigger integer = x + 1 = -15 + 1 = -14
Hence required smaller integer = -15 and required equation is x + (x + 1) = -29
Answer:
n=28
Step-by-step explanation:
Casey has n number of movies. James has 1 1/2 times or 1.5n movies. Since James has 42 then 1.5n = 42. Solve for n to find Casey's. Casey has 28.
