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IgorLugansk [536]
3 years ago
11

PLEASE HELP!!!!!!!!!!!!!!!

Mathematics
1 answer:
Dahasolnce [82]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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Jesse bought 10 more pencils than erasers. A pencil costs $0.15 and an eraser costs $0.22. He paid a total of $4.46. How many er
VARVARA [1.3K]

“Jesse bought 10 more pencils than erasers”       means    P = 10 + E

 “A pencil costs $0.15”   means that     $0.15*P was spent on pencils

 “an eraser costs $.22”    means that    $0.22*E was spent on erasers

 “He paid a total of $4.46”    means that   $0.15*P + $0.22*E = $4.46

15*(10+E)   +   22*E    =   446

                       150 + 37E = 446

                          37E = 296

                              E = 8   Jesse bought 8 erasers

8 0
3 years ago
To transmit information on the internet, large files are broken into packets of smaller sizes. Each packet has 1,500 bytes of in
erastova [34]

Answer: x= 187.5p

Step-by-step explanation:

Given : An equation relating packets to bytes of information : b = 1,500p where<em> p</em> represents the number of packets and <em>b</em> represents the number of bytes of information.

1 byte = 8 bits

Let x= Number of bits such that 1 b = 8x

Put b = 8x in given equation , we get

8x=1500p

Divide both sides by 8 , we get

x= 187.5p

Hence, the equation represent the relationship between the number of packets and the number of bits : x= 187.5p

3 0
3 years ago
Read 2 more answers
Which equation represents this statement? Fourteen less than three times a number is fifty-two. A) 3x −14 = 52 B) 3x + 14 = 52 C
zalisa [80]

Answer:

A

Step-by-step explanation:

This sentences implies that to a number multiplied by 3 ( three times a number) 14 needs to be subtracted.

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Simplify completely. (c^6/c^2)5 Enter your answer in the box.
saveliy_v [14]

the anwser is 36...................

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Best definition combining like terms
makkiz [27]
<span>A letter that holds the place for some unknown value in mathematics VARIABLE A process where you must look for terms that have identical variable parts and then combine their coefficients. COMBINING LIKE TERMS</span>
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