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IgorLugansk [536]
3 years ago
11

PLEASE HELP!!!!!!!!!!!!!!!

Mathematics
1 answer:
Dahasolnce [82]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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Work out the surface area of this solid prism
zalisa [80]

Answer:

3220 cm²

Step-by-step explanation:

Lets find the area of the two triangles

I am making a modification:

Both of the triangles are the same, so I wont divide by 2 using the area of triangle formula 1/2(b * h) because we end up multiply by 2

Area of triangles = 15 cm x 28 cm = 420 cm²

Area of front facing parallelogram = 24 cm x 4(10)cm = 100(10)cm = 1000 cm²

Area of back facing parallelogram = 17 cm x 40 cm = 680 cm²

Area of bottom parallelogram = 40 cm x 28 cm = 1120 cm²

Total Surface area = 420 cm² + 1000 cm² + 680 cm² + 1120 cm² = 1100 cm² + 2120 cm² = 3220 cm²

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
3 years ago
Please help me asap.​
VLD [36.1K]

Answer

-7

Step-by-step explanation:

from what I understand you sub 0 by x

so 0-7

this will give -7

7 0
3 years ago
Read 2 more answers
What is the unit rate of 2 2/3?
inn [45]

Answer:

2,6

Step-by-step explanation:

2 2/3 means 2 + 2/3

2 2/3 = 8/3

8/3 = 2,6

So 2 2/3 = 2,6

6 0
3 years ago
Write the multiplication equation that the diagram represents
Maurinko [17]
1/2 times 1/2 is your answer, because all the diagrams represent that
6 0
3 years ago
Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
LuckyWell [14K]

Answer:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

df = n_1 +n_2 -2 = 10+15-2= 23

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

\bar X_1 = 1085 sample mean for group 1

\bar X_2 = 1034 sample mean for group 2

n_1 = 10 sample size for group 1

n_2 = 15 sample size for group 2

s_1 = 52 sample deviation for group 1

s_2 = 61 sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0
3 years ago
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