1. 5m+3n=41
3m-6n=9 (multiplying the first equation by 3 and the second by 5), we get;
15m+9n=123
15m-30n= 45 (subtracting the two equations)
39n = 78
n = 2, and
to get m we substitute n with 2
3m = 9+6(2)
3m = 21
m = 7
Therefore, n=2 and m=7
2. 6g +8h=40
-6g +2h = -20(Adding the two equations to eliminate g)
10 h= 20
h =2
to get g we substitute h with two
6g= 40- 8(2)
= 24
g= 4
Therefore, g =4 and h =2
3. 9x +5y =35
2x + 5y =0 (subtracting the two equations to eliminate y)
7x =35
x= 5
To get y we substitute x with 5
5y=35-9(5)
5y = -10
y = -2
Therefore, x=5 and y=-2
The answer to this equation is 27 because this is the highest number or the maximum value you can reach with this equation.
I hope this helps!!!!!!
Step-by-step explanation:
The angle of incidence is equal to the angle of reflection.
So if the total angle ROQ = i+r = 124. The angle of reflection, r must be half of this = 62.
Angle POK is a right angle, so to find angle ROK, we do 90-62 = 28
Answer:
Step-by-step explanation:
1. k - 5
2. 31g
3. b - 43
4. u - 36
5. 15r
6. 21/q
7. 7 + j or j + 7
8. 33/n
9. a + 23
10. 44m
11. c + 15
12. 10 -f
13. 39/e
14. k - 29
15. s - 38
16. v + 28
17. x - 11
18. y + 26
It’s b
it’s not A because it’s not percentages it’s decimals using boxes as an example
