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boyakko [2]
2 years ago
5

The following equation was correctly simplified:

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
6 0

Answer:

Step-by-step explanation:

it is -6x2 not plus

if my answer helps please mark as brainliest.

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B. segment AG is congruent to segment OL

Step-by-step explanation:

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Let n be a number of friends at the perty. If <span>dinner costs $30 per person, then it cost $30n for all friends.
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A clothing business finds there is a linear relationship between the number of shirts, n , it can sell and the price, p , it can
kipiarov [429]

Answer:

  p = -0.002n +145

Step-by-step explanation:

You are given two points: (n, p) = (46000, 53) and (50000, 45). The 2-point form of the equation of a line is useful for this.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  p = (45 -53)/(50000 -46000)(n -46000) +53

  p = -8/4000(n -46000) +53

  p = -0.002n +145 . . . . . demand equation

7 0
3 years ago
A light bulb company produces a constant number of new light bulbs in their factory each week, and stores them in a warehouse wh
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3 years ago
A ship is stationary at sea. A tugboat is 28 km away at a bearing of 210°, and a yacht is 24 km from the tugboat at a bearing of
3241004551 [841]

Answer:

The distance between the yacht from the ship is about 33.6 km.

Step-by-step explanation:

The diagram is attached below.

Point A is the shipe, Point B is the tugboat, and Point C is the yacht.

Since the tugboat is 28 km away, and the scale being used is 1 cm : 4 km, the tugboat is 7 cm away from the ship at a 210° bearing on the diagram.

Likewise, the yacht is 6 cm away from the tugboat at a 210° bearing.

To find the distance between the yacht to the ship, we need to

yacht to the ship, we need to determine the value of x.

To do so, we can use the Law of Cosines:

b²a² + c²2ac cos(B) =

First, we need to determine ZB.

A has a bearing of 210°. 180° is covered by QI and IV. So, the small angle in QIII is 30°.

By Alternate Interior Angles, the angle in QI (inside the triangle) of Point B must also be 30°.

And since Point B has a bearing of 310°, 270° is covered in total by QI, QIV, and QIII. So, 40° is left in QII.

Therefore, 50° is the measure of the angle in QIII within the triangle of Point B.

Thus, ZB measures 50° + 30° = 80°.

So, ZB measures 80°. We also know that a = 6 and c= 7. Substitute:

b² = (6)² + (7)² - 2(6)(7) cos(80)

Simplify and take the square root of both sides. So:

b = √85-84 cos(80)

Approximate using a calculator:

b = 8.3912... ≈ 8.39 cm

Since 1 cm: 4km, to find the distance in km, we simply need to multiply by four. So:

⇒b= 4(8.3912...) = 33.5651 ≈

33.6 km

The distance between the yacht from the ship is about 33.6 km.

Step-by-step explanation:

hope it helps you itz admirer

4 0
2 years ago
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