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horrorfan [7]
2 years ago
6

A truck can be rented from Company A for $120 a day plus $0.70 per mile. Company B charges $80 a day plus $0.90 per mile to rent

the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
Mathematics
1 answer:
Readme [11.4K]2 years ago
5 0

Answer:

200 miles

Explaination:

in order to fiind the point of interaction you must put the world problem into an liner equation.

y=mx+b

key:

miles : x

y= 0.70x + 120

&

y= 0.90x + 80

now you put them together

0.70x + 120 = 0.90x + 80

-0.70x. -0.70x

____________________ subtract slope from both sides

120 = 0.20x + 80. ( doesn't matter which one)

-80 - 80

____________________ subtract

40 = 0.20x

_________ Divide each # with the slope

0.20 0.20

200 = x

hope this helps!

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If the equation ax+b=cx+d has no solution what must be true about a, b, c, and d?
kykrilka [37]

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Answer:

  • a = c
  • b ≠ d

Step-by-step explanation:

For there to be no solution, the lines represented by the left-side and right-side expressions must be parallel. That is, the coefficients of x must be identical,

  a = c

and the y-intercepts must be different:

  b ≠ d.

5 0
2 years ago
This is urgent can someone please help.......
enyata [817]

Answers are c, a, and c

8 0
2 years ago
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Solve the problem.
RSB [31]
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2 years ago
If x=2/3 and x=-3 are the roots of the equation ax^2+7x+b=0 find the values of a and b
Gnesinka [82]

<u>ANSWER:  </u>

If x = \frac{2}{3} and x = -3 are the roots of the equation, then values of a and b are 3, -6

<u>SOLUTION: </u>

Given, quadratic equation is a x^{2}+7 x+b=0 and its roots are -3 , \frac{2}{3}

We know that, for any quadratic equation of form a x^{2}+b x+c=0 with roots x_{1} and x_{2} then,

Sum of roots (x_{1} +x_{2}) = \frac{-b}{a}

Product of roots ( x_{1} \times x_{2}) = \frac{c}{a}

Now, for given quadratic equation x_{1} = -3 and x_{2} = \frac{2}{3}

hence Sum of roots = \frac{-7}{a}

x_{1} + x_{2} = \frac{-7}{a}

-3 + \frac{2}{3} = \frac{-7}{a}

on solving we get "a" = 3

Now product of roots = x_{1} \times x_{2} = \frac{b}{3}

-3 \times \frac{2}{3} = \frac{b}{3}

b = -6

hence, the values of a and b are 3, -6.

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3 years ago
Briana walks 3/4 miles in 1/5 hour.How much did she walk in 1 hour?
kykrilka [37]
In one hour she will walk 3 3/4 miles.
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