The scale factor is 1/3.
To find this scale factor, choose a set of sides to compare lengths. For example, taking the left sides of the triangles, which is 9 and 3. 9 is 3 times bigger than the triangle on the right, so that gives us the scale factor of 1/3.
It takes value from a user and then user the operation of (+,-,*/).
i used c++ programming language to solve this program:
#include<iostream>
using namespace std;
int main() {
int var1, var2;
char operation;
cout << "Enter the first number : ";
cin >> var1;
cout << endl;
cout <<"Enter the operation to be perfomed : ";
cin >> operation;
cout << endl;
cout << "Enter the second nuber : ";
cin >> var2;
cout << endl;
bool right_input = false;
if (operation == '+') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 + var2);
right_input = true;
}
if (operation == '-') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '*') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 * var2);
right_input = true;
}
if (operation == '/' && var2 != 0) {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '/' && var2 == 0) {
cout << "Error. Division by zero.";
right_input = true;
}
if (!right_input) {
cout << var1 << " " << operation << " " << var2 << " = " << "Error;";
cout << "Invalid Operation!";
}
cout << endl;
system("pause");
return 0;
}
Answer:
0
Step-by-step explanation:
1^2=1
2^2=4
3^2=9
We can stop here because the from here on forward they are bigger than 10 itself.
Answer:
X = 2.75 or 2 3/4 in fraction form
Step-by-step explanation:
We know that the variable X has to make both equations equal.
It is really just crossing out the options.
2.75 can fit in the X variable because if 2.75 was in both equations, the answer would be the same.
So the answer is 2.75
Hope this helps! :)
૮ ・ﻌ・ა
Answer: x = 1
Step-by-step explanation:
2log(x+1) - log (x+3) = log 1
log(x+1)^2 - log (x+3) = log 1
log [(x+1)^2 / (x+3)] = log 1
(x+1)^2 / (x+3) = 0
(x+1)^2 = 0
x = 1 or x = -1 (rejected, as log0 does not exist)
