Answer:
The required biconditional statement is: If Smith is guilty, if and only if Jones is innocent.
Step-by-step explanation:
From the provided statement.
The statement is: If Smith is guilty, then Jones is innocent.
The converse is: If Jones is innocent, then Smith is guilty.
The combination of a conditional statement and its converse is called biconditional statement.
The biconditional statement contains if and only if phrase between two part of the statement.
Which means the statement and converse both are true.
Therefore, the required biconditional statement is: If Smith is guilty, if and only if Jones is innocent.
Answer:
I believe it is 252 correct me if I'm wrong
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Answer:
6/5 miles per hour or 1.2 miles per hour
Step-by-step explanation:
If Natalie walked 3/5 miles in 1/2 hour, then in 1 hour she would have walker 6/5 miles(3/5 * 2). You can write 6/5 as 1.2 (6 divided by 5). Thus, Natalie walked 1.2 miles per hour
It's D, it's the only one where it has a -6 at the end other than A, but if you look at the A when distributed there isn't a 23x<span />
