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3 years ago

A cone has a height of 15 inches and a radius of 12 inches. What is its volume?

Mathematics

1 answer:

Elena L [17]3 years ago

4 0

Answer:

V ≈ 7186 in³

Step-by-step explanation:

The volume of a cone of base radius r and height h is V = (1/3)(π)(r^2)(h).

When h = 15 in and r = 12 in, the volume of the cone is

V = (1/3)(π)(12 in)²·(15 in), or approximately V ≈ 7186 in³

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For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14

For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6

Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:

(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1

So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.

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3 years ago

FInd the value of x. Y D W X (15x-8) X = N 226

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Let's start with the given arc and its angle.

The angle YWX is going to be half the arc length.

YWX = 1/2 (226) = 113

Angles VWX and YWX form a linear pair (or are supplementary angles), which means that their sum is 180 degrees.

(15x - 8) + 113 = 180

15x + 105 = 180

15x = 75

x = 5

Hope this helps!

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2 years ago

For a history fair, a school is building a circular wooden stage that will stand that will stand 2 feet off the ground . Find th

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3 years ago

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12 : 4 = 3 km her speed per hour
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4 years ago

you send 12 photos to a company that makes personalized wall calendars the company enlarges the photos and inserts one for each

Assoli18 [71]

Answer:

15 inches

Step-by-step explanation:

We have that,

Length of the photo = 4 inches and Width of the photo = 6 inches

Also, the width of the image on the calendar = 10 inches

Let, the length on the image of the calendar = x inches.

Since, the ratio of the photo and its image will remain same, we get,

$\frac{4}{6}=\frac{10}{x}$

i.e. $x=\frac{60}{4}$

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Hence, the length of the image of the photo on the calendar is 15 inches.

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3 years ago