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4 years ago

7

Each day at lunchtime. At least 53 people buy food from a food truck. Using the variable P, an inequality that represents that s

ituation is.....

1 answer:

Artyom0805 [142]4 years ago

7 0

p ≥ 53.
p is at least 53

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The wool sold 4038 tickets to their soccer game the leopard sold 6224 tickets to their game how many more tickets did the leopar

andrew11 [14]

Leopard sold 2186 more tickets than the wolf

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3 years ago

Plz help, 15 points!

Eduardwww [97]

Answer:

$2x+3y=-6$

Step-by-step explanation:

Let the line is $y=mx+b$ where $m$ is slope and $b$ is $y-intercept$ .

The line is parallel to $2x+3y=3$ , slope of both the lines will be same.

Find the slope of $2x+3y=3$

$3y=3-2x\\y=-\frac{2}{3}x+1$

Slope of line $=-\frac{2}{3}$

$m=-\frac{2}{3}$

So the line will be $y=-\frac{2}{3}x+b$

It passes through $(3,-4)$ .

$-4=-\frac{2}{3}\times 3+b\\-4=-2+b\\b=-2\\$

Hence the line is $y=-\frac{2}{3}x-2$

$y=-\frac{2}{3}x-2\\3y=-2x-6\ \ \ \ \ \ \ (Multiply both sides by 3)\\2x+3y=-6$

6 0

3 years ago

Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY

Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

$\overline{AC}\cong \overline{AB}$ - given
$\angle CAX\cong \angle BAX$ - given
$\overline{AX}\cong \overline{AX}$ - reflexive property

By SAS postulate, $\triangle CAX\cong \triangle BAX$

Congruent triangles have conruent corresponding parts. So,

$\overline{CX}\cong \overline{BX}$

Consider triangles CXY and BXY. In these triangles,

$\overline{CX}\cong \overline{BX}$ - proven
$\angle CXY\cong \angle BXY$ - given
$\overline{XY}\cong \overline{XY}$ - reflexive property

By SAS postulate, $\triangle CXY\cong \triangle BXY$

Congruent triangles have conruent corresponding parts. So,

$\angle XCY\cong \angle XBY$

5 0

3 years ago

For each sequence find the first 4 terms and the 10th term

jolli1 [7]

Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:

a) 1 (1st term) + 5 = 6

2 (2nd term) + 5 = 7

3 (3rd term) + 5 = 8

4 (4th term) + 5 = 9

10 (10th term) + 5 = 15

And so on for b (not going to keep writing the term, I’m sure you get that by now.

b) 2(1) - 1 = (2x1) - 1 = 1

2(2) - 1 = (2x2) - 1 = 3

2(3) - 1 = (2x3) - 1 = 5

2(4) - 1 = (2x4) - 1 = 7

2(10) - 1 = (2x10) - 1 = 19

Hope this helps :)

4 0

3 years ago

A student wants to find point C on the directed line segment from A to B on a number line such that the segment is partitioned i

olganol [36]

Answer:

<u>Point C at (-18/7)</u>

Step-by-step explanation:

Point A is at -6 and point B is at 2.

So, the distance between A and B = 2 - (-6) = 8

point C on the directed line segment from A to B on a number line such that the segment is partitioned in a ratio of 3:4.

Let the distance AC = x

∴ BC = 8 - x

AC : CB = 3 : 4

∴ $\frac{AC}{CB} =\frac{3}{4} = \frac{x}{8-x}$

Using cross multiplication

3 (8-x) = 4x

24 - 3x = 4x

24 = 7x

x = 24/7

So, Point C = -6 + 24/7 = -18/7

Point C at (-18/7)

7 0

3 years ago

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