Please help me with this, thanks !!

Assume that the Poisson distribution applies and that the mean number of aircraft accidents is 9 per month. Find P(0), the prob

Ugo [173]

Answer: 0.0001

It is unlikely to have a month with no aircraft accidents .

Step-by-step explanation:

Given : Mean number of aircraft accidents = 9 per month

The Poisson distribution formula :-

$\dfrac{e^{-\lambda}\lambda^x}{x!}$ , where $\lambda$ is the mean of the distribution.

If X = the number of aircraft accidents per month, then the probability that in a month, there will be no aircraft accidents will be :-

$\dfrac{e^{-9}(9)^0}{0!}=0.000123409804087\approx0.0001$

Hence, the probability that in a month, there will be no aircraft accidents = 0.0001

Since this is less than 0.5 , therefor it is unlikely to have a month with no aircraft accidents .

5 0

3 years ago

#7) Solve 8c - 3c + 3 = 13.

nordsb [41]

Hello!

$\large\boxed{c = 2}$

8c - 3c + 3 = 13

Begin by combining like terms:

5c + 3 = 13

Subtract 3 from both sides:

5c + 3 - 3 = 13 - 3

5c = 10

Divide both sides by 5:

5c/5 = 10/5

c = 2.

6 0

3 years ago

Can someone please help me with this problem!

Anna71 [15]

Answer:

11 yards

Step-by-step explanation:

The volume of a cone formula is:

$V=\frac{1}{3}\pi r^2 h$

Where V is the volume,

r is the radius (half of diameter)

h is the height

Given,

h = 15

V = 475.17

We find the radius (r) first by substituting given values:

$V=\frac{1}{3}\pi r^2 h\\475.17=\frac{1}{3}\pi r^2 (15)\\475.17=5\pi r^2\\r^2=30.25\\r=5.5$

The radius (r) is 5.5 yards

We need the diameter, which is DOUBLE THE RADIUS, so diameter would be:

Diameter = 5.5 * 2 = 11 yards

8 0

3 years ago

PLSSSS HELP IVE TRIED EVERYTHING AHHHHHHH

stepladder [879]

Answer:

<u>Domain</u>: input values (x-values)

<u>Range</u>: output values (y-values)

<u>Increasing function</u>: the average rate of change is positive

<u>Decreasing function</u>: the average rate of change is negative

<u>Constant function</u>: y-values do not vary, regardless of x-values

<h3><u>Graph 1</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2, 2]

Increasing function: (-2, 0)

Decreasing function: (0, 3)

<h3><u>Graph 2</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2.5, 2]

Increasing function: (-2, -1) ∪ (1.5, 3)

Decreasing function: (-1, 1.5)

<h3><u>Graph 3</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-1, 2]

Increasing function: (-2, -1)

Constant: (-1, 1)

Decreasing function: (1, 3)

5 0

2 years ago

In kite PQRS , TQ=3 cm and TP=4 cm. What is SP ? Enter your answer in the box.

yawa3891 [41]

Answer:

Kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent

Given: In kite PQRS

where PR and SQ are the diagonals of Kite respectively as shown in the figure given below.

Given: TQ = 3 cm and TP = 4 cm

Let PR is the main diagonal and SQ is the cross diagonal of kite PQRS as shown in figure, also let T is the intersection point of PQRS.

By Property of Kite, diagonal SQ bisects PR at perpendicular angle i.e, 90 degree.

i,e

Then, in right angle ΔQTP

$PQ = \sqrt{TQ^2+TP^2}$ [Using Pythagoras theorem]

Substitute the given values of TQ and TP we have;

$PQ = \sqrt{3^2+4^2} =\sqrt{9+16} =\sqrt{25} = 5 cm$

Also, PQ = SP [by definition of kite]

therefore, the side SP = 5 cm.

4 0

3 years ago

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