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3 years ago

What is the amplitude of the graph of

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

4 0

It is 2 :)
Y=A sin(B(x+C))+D

Where A is equal to the amplitude.

Would appreciate brainliest answer :)

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Select the term that best describes the statement A triangle is acute provided all the angles have a measure of less than 90 deg

Aloiza [94]

I think the correct answer is conjunction...

4 0

3 years ago

Read 2 more answers

Plz help ILL GIVE BRAINLIEST

vovangra [49]

Answer:

Step-by-step explanation:

I think in this question we have to find slope, if so, its y = 10x.

to find the slope just pick two numbers, i chose (2,20) and (7,70) and then put them in the slope formula y2-y1/x2-x1. That gave me 10. I hope its correct. :)

7 0

3 years ago

What is the solution to this expression<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Bx%5E%7B2%7D%20%5Ccdot%20t%7D%20%20%5Cf

ankoles [38]

Answer:

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Step-by-step explanation:

6 0

4 years ago

Evaluate the expression

larisa86 [58]

Answer:

$12-[20-2(6^2\div3\times2^2)]=88$

Step-by-step explanation:

So we have the expression:

$12-[20-2(6^2\div3\times2^2)]$

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

$12-[20-2(6^2\div3\times2^2)]$

The parentheses is:

$(6^2\div3\times2^2)$

Square the 6 and the 4:

$(36\div3\times4)$

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

$(36\div3\times4)\\=(12\times4)\\=48$

Therefore, the original equation is now:

$12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]$

Multiply with the brackets:

$=12-[20-96]$

Subtract with the brackets:

$=12-[-76]$

Two negatives make a positive. Add:

$=12+76=88$

Therefore:

$12-[20-2(6^2\div3\times2^2)]=88$

3 0

4 years ago

Write any Quetion for the following transformation of Y equals X a vertical compression by factor of 1/4

irina [24]

Suppose that X is a vertical segment that lies on the y-axis with its beginning at origin and ending at the point (0,4). Then the length of this segment is 4 units.
If you vertically compress this segment by factor of 1/4 with the centre of compression at the origin, you recieve a segment that also lies on the y-axis with its beginning at origin and ending at the point (0,1) (the length of this image segment is 1 unit).
So, the question is: if a segment that lies on the y-axis with its beginning at origin and ending at the point (0,4) is vertically compressed <span>by factor of 1/4 with the centre of compression at the origin, what is the image of this transformation?
</span>

7 0

3 years ago