Help me please and thank you

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

3 0

Answer:

i HoNesTlY doNT kNow BuT thANks 4 tHe pONIts

Step-by-step explanation:

Just answer the question

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Vaimiti walks at a constant pace of 1.1 m/s and takes 25 minutes to get to school.

Temka [501]

Solution:

Note that:

Speed = Distance/Time
Vaimiti speed = 1.1 m/s
Jabril speed = 1.3 m/s

Converting the time (minutes to seconds) for Vaimiti to reach school:

Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
=> Vaimiti's time to reach school: 1500 seconds

Converting the time (minutes to seconds) for Jabril to reach school:

Jabril's time to reach school: 30 minutes = 30 x 60 seconds
=> Jabril's time to reach school: 1800 seconds

Finding the distance of Vaimiti:

Speed = Distance/Time

Important: The distance will be in meters since the speed units is meters/seconds.

=> 1.1 meters/second = Distance/1500
=> 1.1 x 1500 = Distance
=> 1650 meters = Distance (In meters)

Finding the distance of Jabril:

Speed = Distance/Time

Important: The distance will be in meters since the speed units is meters/seconds.

1.3 meters/second = Distance (In meters)/1800 seconds
=> 1.3 x 1800 = Distance (In meters)
=> 2340 meters = Distance (In meters)

This can lead to two possible solutions:

Possible solution #1:

Finding the difference between the two distances:

2340 meters - 1650 meters = Difference (In meters)
=> 690 meters

Possible solution #2:

The difference between the distances they walked is that Jabril walked faster than Vaimiti, but Vaimiti reached school earlier than Jabril because the walking distance for Vaimiti is less than the walking distance for Jabril.

Hoped this helped!

6 0

3 years ago

Read 2 more answers

Find the value of x in the picture below.

lilavasa [31]

Answer:

I think that the answer is 2.5 , the second item .

4 0

3 years ago

Solve this equation for x. 2/3(x+8)^2-66=0

yKpoI14uk [10]

Answer:

$\large\boxed{x=-8\pm3\sqrt{11}}$

Step-by-step explanation:

$\dfrac{2}{3}(x+8)^2-66=0\qquad\text{add 66 to both isdes}\\\\\dfrac{2}{3}(x+8)^2-66+66=0+66\\\\\dfrac{2}{3}(x+8)^2=66\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{2}{3\!\!\!\!\diagup_1}(x+8)^2=(3)(66)\\\\2(x+8)^2=198\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup^1(x+8)^2}{2\!\!\!\!\diagup_1}=\dfrac{198\!\!\!\!\!\diagup^{99}}{2\!\!\!\!\diagup_1}\\\\(x+8)^2=99\iff x+8=\pm\sqrt{99}\qquad\text{subtract 8 from both sides}$