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3 years ago

The following table shows the number of hours some high school students in two states spend surfing the Internet each week:

1 answer:

7 0

1st data set:

Minimum: 34
1st quartile: 35
Median: 36
3rd quartile: 37
Maximum: 38

Second data set:
Minimum: 20
1st quartile: 23
Median: 25
3rd quartile: 38
Maximum: 65

Graph it based on the values of the 1st and 3rd quartile. If they are both the same number away from the mean then they are symmetrical. Otherwise they are not. In this case, the first one is similar and the second one is not.

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What does B.O.D.M.A.S. or B.E.D.M.A.S. mean?

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3 years ago

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Please help me with the worksheet

aivan3 [116]

Answer:

9) a = ¾, <u>vertex</u>: (-4, 2), <u>Equation</u>: y = ¾|x + 4| + 2

10) a = ¼, <u>vertex</u>: (0, -3), <u>Equation</u>: y = ¼|x - 0| - 3

11) a = -4, <u>vertex</u>: (3, 1), <u>Equation</u>: y = -4|x - 3| + 1

12) a = 1, <u>vertex</u>: (-2, -2), <u>Equation</u>: y = |x + 2| - 2

Step-by-step explanation:

I could <u><em>only</em></u> work on questions 9, 10, 11, 12 in accordance with Brainly's rules. Nevertheless, the techniques demonstrated in this post applies to all of the given problems in your worksheet.

<h2><u>Definitions:</u></h2>

The given set of graphs are examples of absolute value functions. The <u>general form</u> of absolute value functions is: y = a|x – h| + k, where:

|a| = determines the vertical stretch or compression factor (wideness or narrowness of the graph).

(h, k) = vertex of the function

x = h represents the axis of symmetry.

<h2><u>Solutions:</u></h2><h3>Question 9) ⇒ Vertex: (-4, 2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (0, 5) and substitute into the general form (equation):

y = a|x – h| + k

5 = a| 0 - (-4)| + 2

5 = a| 0 + 4 | + 2

5 = a|4| + 2

5 = 4a + 2

Subtract 2 from both sides:

5 - 2 = 4a + 2 - 2

3 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{3}{4}\:=\:\frac{4a}{4}}$

a = ¾

Therefore, given the value of a = ¾, and the vertex, (-4, 2), then the equation of the absolute value function is:

<u>Equation</u>: y = ¾|x + 4| + 2

<h3>Question 10) ⇒ Vertex: (0, -3)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -2) and substitute into the general form (equation):

y = a|x – h| + k

-2 = a|4 - 0| -3

-2 = a|4| - 3

-2 = 4a - 3

Add 3 to both sides:

-2 + 3 = 4a - 3 + 3

1 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{1}{4}\:=\:\frac{4a}{4}}$

a = ¼

Therefore, given the value of a = ¼, and the vertex, (0, -3), then the equation of the absolute value function is:

<u>Equation</u>: y = ¼|x - 0| - 3

<h3>Question 11) ⇒ Vertex: (3, 1)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -3) and substitute into the general form (equation):

y = a|x – h| + k

-3 = a|4 - 3| + 1

-3 = a|1| + 1

-3 = a + 1

Subtract 1 from both sides to isolate <em>a</em>:

-3 - 1 = a + 1 - 1

a = -4

Therefore, given the value of a = -4, and the vertex, (3, 1), then the equation of the absolute value function is:

<u>Equation</u>: y = -4|x - 3| + 1

<h3>Question 12) ⇒ Vertex: (-2, -2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (-4, 0) and substitute into the general form (equation):

y = a|x – h| + k

0 = a|-4 - (-2)| - 2

0 = a|-4 + 2| - 2

0 = a|-2| - 2

0 = 2a - 2

Add 2 to both sides:

0 + 2 = 2a - 2 + 2

2 = 2a

Divide both sides by 2 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{2}{2}\:=\:\frac{2a}{2}}$

a = 1

Therefore, given the value of a = -1, and the vertex, (-2, -2), then the equation of the absolute value function is:

<u>Equation</u>: y = |x + 2| - 2

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2 years ago

if the square roots of the natural numbers from 1 to 200 are calculated what will be the whole numbers

Mamont248 [21]

Answer:

Step-by-step explanation:

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3 years ago

Factor 1/3 out of 1/3p-2/3 please answer this! Easy 20 points!

Tju [1.3M]

Answer:

$\frac{1}{3} (\frac{1}{p} - 2)$

Step-by-step explanation:

Given the equation = $\frac{1}{3p} - \frac{2}{3}$

Required: To factor out 1/3;

$\frac{1}{3p} - \frac{2}{3}$

1/3 is common to both sides;

So, 1/3 is a common factor

$\frac{1}{3} (\frac{1}{p} - 2)$

To solve for the value of p;

$\frac{1}{3} (\frac{1}{p} - 2)$ = 0

$\frac{1}{p} - 2 = 0$

$\frac{1}{p} = 2$

$1 = 2p$

$p = \frac{1}{2}$

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3 years ago

Which shows the four-term polynomial and factored form of x2 + 6x – 27?

mixas84 [53]

We need to understand that the sign of your constant )that's your number -27) dictates how you factor. A + and - number multipled together yields a - number.

The middle term dictates what number is asigned the + or - signs. Knowing that are 6 is positive, the larger number will be assigned the positive sign.

So what to numbers multiply together to yield- 27, but have a difference of +6. +9 x -3 = -27

Therefore, we break our binomial up as follows, (x+9)(x-3)

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3 years ago

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