Step-by-step explanation:
Answer:
Y=21
Step-by-step explanation:
add 13 on both sides you get Y=21
Substitute each value of x in y=2x-3
so,
first box (-2)
y= 2(-2)-3
y= -4-3
y= -7
second box (0)
y= 2(0)-3
y= 0-3
y= -3
third box (3)
y=2(3)-3
y=6-3
y=3
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
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If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
