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3 years ago

Round the following factors to estimate the products

Mathematics

1 answer:

poizon [28]3 years ago

7 0

Step-by-step explanation:

597 rounding would be 600 while 52 would be 50.

So 600 x 50

= 30,000

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Find the distance between the points. Round to the nearest tenth.<br> (1, 3) and (5.0)

Anna35 [415]

Answer:

1,2. 6.0

Step-by-step explanation:

That is the answer

5 0

3 years ago

Read 2 more answers

Please Help me!!!

drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

$d=2t^3+5t^2-3$

Displacement at t = 4 hours,

$d(4)=2(4)^3+5(4)^2-3=205\ km$

Velocity of particle is given by :

$v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t$

Velocity at t = 4 hours,

$v=6(4)^2+10(4)=136\ km/h$

Acceleration of the particle is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10$

At t = 4 hours,

$a=12(4)+10=58\ km/h^2$

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0

3 years ago

The formula A=200e^.033t models the population of a particular city, in thousands, t years after 1998. When will the population

svetoff [14.1K]

Answer:

In the year 2010

Step-by-step explanation:

we have

$A=200e^{0.033t}$

where

A is the population in thousands

t is the number of years since 1998

For A=297 thousands

substitute and solve for t

$297=200e^{0.033t}$

simplify

$1.485=e^{0.033t}$

Apply ln both sides

$ln(1.485)=ln[e^{0.033t}]$

$ln(1.485)=(0.033t)ln(e)$

Remember that

$ln(e)=1$

$ln(1.485)=(0.033t)$

$t=\frac{ln(1.485)}{0.033}$

$t=12\ years$

1998+12=2010

7 0

3 years ago

Rewrite 81 as a square or a cube

kolbaska11 [484]

9 squared is 81
81=9^2
Or, (3^2)^2. Double square!

5 0

3 years ago

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Y=-3(x – 4)(x – 4) in standard form

dexar [7]

Answer:

It’s already in standard form

Step-by-step explanation:

3 0

3 years ago