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vaieri [72.5K]
2 years ago
12

Round the following factors to estimate the products

Mathematics
1 answer:
poizon [28]2 years ago
7 0

Step-by-step explanation:

597 rounding would be 600 while 52 would be 50.

So 600 x 50

= 30,000

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Find the common difference if the 8th term is 55 and the first term is 13
Vlad [161]

Answer:

Step-by-step explanation:

Equation

L = a + (n - 1)*d

Givens

L = 55

a = 13

n =8

Solution

55 = 13 + (8 - 1)*d               Combine

55 = 13 + 7d                       Subtract 13 from both sides

55 - 13 = 7d

42 = 7d                               Divide by 7

d = 6

6 0
3 years ago
BRAINLIEST FOR CORRECT ANSWER, IM FAILING SCHOOL AND NEED HELP ASAP. EVEN OFFICIAL HELP COUNTS
Delvig [45]

Answer:

x=76

Step-by-step explanation:

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8 0
3 years ago
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34x+95=3(14x+9) what is the answer
Yanka [14]

34x+95=3(14x+9)

We move all terms to the left:

34x+95-(3(14x+9))=0

We calculate terms in parentheses: -(3(14x+9)), so:

3(14x+9)

We multiply parentheses

42x+27

Back to the equation:

-(42x+27)

We get rid of parentheses

34x-42x-27+95=0

We add all the numbers together, and all the variables

-8x+68=0

We move all terms containing x to the left, all other terms to the right

-8x=-68

x=-68/-8

x=8+1/2

   

6 0
3 years ago
Solve 2p^4+6p^3-8p^2-4p
Arte-miy333 [17]
<em>= 2p ( p³ + 3p²  - 4 p - 2 ) Simplified</em>
5 0
3 years ago
Solve S= lw + wh+ lh for h. Hint: Use the distributive property to factor out h.<br> the<br> vcloc
Ostrovityanka [42]

Answer:

{ \rm{S = lw + wh + lh}}

• Group the h terms by organised term arrangement :

{ \rm{S = (wh + lh) + lw}}

• Then using distributive property, factorise out the value h so that the reverse is true.

{ \rm{S = h(w + l) + lw}}

• for the variable "lw", divide it by h in order to add it to the bracket of (w + l). Make sure the reverse is true:

{ \rm{S = h(w + l) + h( \frac{lw}{h} )}} \\

• finally, completely factorise out the value h

\hookrightarrow \: \: { \boxed{ \boxed { \rm{ \:  \: S = h(w + l +  \frac{lw}{h} ) \:  \: }}}}

4 0
2 years ago
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