Given:
wild turkey ; 12 in the first hour and cumulative number increases by 40% per hour
white-tail deer ; 18 in the first hour and 10 deer each hour after that.
wild turkery: 12 * (1.40)^n-1 ; n is the number of hour
white-tail deer: 18 + 10^n-1 ; n is the number of hour
n wild turkey white-tail deer
1 12 18
2 17 28
3 24 38
4 33 48
5 46 58
6 65 68
7 90 78
It would be hour 7 after sunrise that the cumulative count of the turkeys first exceed the cumulative count of the deer.
Your answer to the question would be g(x)=4x-3
It's 24k-6
By order of operations, you do the multiplication first: 3k(4) = 12k
12k-6+12k now combine like terms
24k-6
Hope that helps
Answer:
wait really ? lol
Step-by-step explanation:
Answer:
0/6 because the arrow start from zero and end at six, remember that the arrow is starting from the vertical axis.....
