Hope it can solve you problem... :)
height,h = 3"
base, b = length, l = 2
area of triangle, t = bxh/2...eqn 1
area of square, s = l^2...eqn 2
area of pyramid, p =4t + s...eqn 3
subst h = 3 and b = 2 in eqn 1
t = 3x2/2 = 3
subst l =2 in eqn 2
s = 2^2 = 4
subst t = 3 & s = 4 in eqn 3
p = 4(3) + 4 = 16sq inch
Answer:
c
Step-by-step explanation:
Answer:
125.92 sq cm
Step-by-step explanation:
You need to find the area of all the sides, so:
2(2.2 * 9.1) + 2(2.2 * 3.8) + 2( 9.1 * 3.8)
= 125.92 sq cm
