If Jay-Jay walks 8 miles in 2 hours on average, how far will he walk if he continues at the same pace for 3 hours?

Which expression is equivalent to 36^-1/2

inn [45]

ANSWER

$( {36})^{ (- \frac{1}{2}) } = \frac{1}{6}$

EXPLANATION

The given expression is

${36}^{( - \frac{1}{2} )}$
This is having a negative index. We must first of all change to a positive index.

Recall that,

${a}^{ - m} = \frac{1}{ {a}^{m} }$

We apply this law of exponents to get,

${36}^{( - \frac{1}{2} )} = \frac{1}{ {36}^{( \frac{1}{2} )} }$

We cab rewrite the given expression to obtain;

${36}^{( - \frac{1}{2} )} = \frac{1}{ \sqrt{36} }$

This will simplify to give us,

${36}^{( - \frac{1}{2} )} = \frac{1}{ 6 }$

6 0

2 years ago

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The number of entrees purchased in a single order at a Noodles & Company restaurant has had an historical average of 1.7 ent

SOVA2 [1]

Answer:

$t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744$

$p_v =P(t_{(47)}>2.744)=0.0043$

If we compare the p value and the significance level given $\alpha=0.02$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=2.1$ represent the mean

$s=1.01$ represent the sample standard deviation

$n=48$ sample size

$\mu_o =1.7$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 1.7, the system of hypothesis would be:

Null hypothesis: $\mu \leq 1.7$

Alternative hypothesis: $\mu > 1.7$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=48-1=47$

Since is a one side test the p value would be:

$p_v =P(t_{(47)}>2.744)=0.0043$

Conclusion

If we compare the p value and the significance level given $\alpha=0.02$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.

4 0

2 years ago

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Simone paid $12 for an initial years subscription to a

AnnZ [28]

You didn’t finish the question

7 0

2 years ago

Please help! Thank you! Also, please explain thank you!

viva [34]

Answer:

2x=10*11

2x=110

so

x=55

5 0

2 years ago

Cora uses 6.2 pints of white paint and blue paint to paint her bedroom walls. 2 5 of this amount is white paint, and the rest is

zhenek [66]

Answer:She used 3.72 pints of blue paints for the wall

Step-by-step explanation:

Total Quantity of Blue and white paint =6.2 pints

Quantity of White paint =2/ 5 x 6.2 pints = 2.48 pints

Quantity of blue paint =Total Quantity -Quantity of White paint

=6.2 pints-2.48 pints

=3.72 pints

5 0

1 year ago