The slope of the line passes through (-6, 3) and (1, 5) is 
<u>Solution:</u>
Given, two points are (- 6, 3) and (1, 5)
We have to find the slope of a line that passes through the above given two points
Slope of a line that pass through 
is given as:
Hence, the slope the line that passes through the given points is
Answer:
(6,35)
Step-by-step explanation:
Set both equations equal to each other and solve for x
8x+11=5x+29, Subtract 5x from both sides
3x+11=29, Subtract 11 from both sides
3x=18 Divide by 3
x=6
Substitute x=6 back into either equation to solve for y
y=8(6)+11
y=48+11
y=59
Answer:
C
Step-by-step explanation:
In a right triangle, the side opposite the right angle is the largest side as the right angle represents the largest angle in the triangle. Therefore, as 17.5 is opposite the right angle, we can say that AB²+10²=17.5², and √(17.5²-10²)=AB = 14.4
Using sohcahtoa, we can establish that
sin(∠C) = opposite/hypotenuse = 14.4/17.5, and
arcsin(14.4/17.5) = ∠C = 55°
Because the angles in a right triangle add up to 180 degrees, we can say that ∠A+∠B+∠C = 180°, so ∠A + 90 + 55 = 180 and ∠A = 35°
50.75
you multiply 14.50 times 3.5
the reason why it is 3.5 is because there are two half hours in one hour, and another half hour plus 15 minutes ( which is half of a half hour)
i hope this is clear!!
good luck!!
