Answer:
B
Step-by-step explanation:
-5[ (x³+1)(x+4) ] = -5[ x³*(x+4) + 1*(x+4) ]
= -5 [ x³*x + x³*4 + 1*x + 1*4 ]
= -5 [ x⁴ + 4x³ + x + 4]
= -5*x⁴ + (-5)*4x³ + (-5)*x + (-5) * 4
= -5x⁴ - 20x³ - 5x - 20
Let <em>x</em> be the amount of salt in the solution.
At day's end, the concentration of salt in the beaker is
<em>x</em> / (4 L) = 0.08 = 8%
Solve for <em>x</em> to get
<em>x</em> = 0.08 (4 L) = 0.32 L
So at the beginning, the concentration of salt in the beaker was
(0.32 L) / (5 L) = 0.064 = 6.4%
Answer:
x=28
Step-by-step explanation:
9514 1404 393
Answer:
- 80
- 40
- 10 to 20, inclusive
Step-by-step explanation:
1. The various goals can be met without filling the theater. This fact means there is a range of possibilities for each of the answers. However, we take the wording, "because of the demand for tickets ..." to mean demand is high and the theater will be sold out.
Since two children's tickets will be sold for each adult ticket sold, the number of children's tickets is 2/3 of the total.
children's tickets = 2/3 × 120 = 80
__
2. The remaining 40 tickets will be adult tickets.
40 adult tickets will be sold.
__
3. The total revenue must be at least $1800. If we allow 'd' tickets to be sold at a discount, then we can find the limits on d using the inequality ...
24(40-d) +24(0.75)d +12(80) ≥ 1800 . . . . revenue from ticket sales
-6d ≥ -120 . . . . . . . . . . . . . . . . . . . collect terms, subtract 1920
d ≤ 20 . . . . . . . . . . divide by -6
At least 10 and at most 20 adult tickets can be sold with a discount.
("At least 10" comes from the problem requirements.)
