Answer:
y = x/10 + 43/10
Step-by-step explanation:
y - y1/ x - x1 = y2 - y1/ x2 - x1
y - 4/ x +3 = 5 - 4/7 + 3
y - 4 / x + 3 = 1/10
10(y - 4) = x + 3
10y - 40 = x + 3
10y = x + 43
y = x/10 + 43/10
This graph will start at (.5, 0) as the vertex.
To find this, all you need to do if find the point where inside the absolute value sign is equal to 0. Since the graph can never have a negative value, this will be the lowest point.
2x - 1 = 0
2x = 1
x = .5
From there, you can plot each point by going up two and to the left one.
Examples of Points: (1.5, 2) and (2.5, 4)
You can also plot the other side of the graph by going up two and to the right one.
These points can be found using the slope, which is the number attached to x (2).
Example of Points (-.5, 2) and (-1.5, 4).
It has 97 amounts.
43,44,45,46,47,48,49,50,
51,52,53,54,55,56,57,58,59,60
61,62,63,64,65,66,67,68,69,70 71,72,73,74,75,76,77,78,79,80
81,82,83,84,85,86,87,88,89,90
91,92,93,94,95,96,97,98,99,100
101,102,103,104,105,106,107,108,109,110
111,112,113,114,115,116,117,118,119,120
121,122,123,124,125,126,127,128,129,
130
131,132,133,134,135,136,137,138,139
Numbers between 42-140
Answer:
x(t) = - 5 + 6t and y(t) = 3 - 9t
Step-by-step explanation:
We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).
Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.
x(t) = - 5 + t and y(t) = 3 - 6t and
x(t) = - 5 + 6t and y(t) = 3 - 9t
Both of the above sets of equations satisfy this above conditions.
Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.
So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t satisfies this condition.
Therefore, this is the answer. (Answer)
