All categories

2 years ago

What percent of 140 is 50?

Mathematics

2 answers:

Rudiy272 years ago

6 0

35.71428571 percent or approximately 35.71%

Inessa [10]2 years ago

4 0

Answer:

35.71%

Step-by-step explanation:

50:140*100 =

(50*100):140 =

5000:140 = 35.71

You might be interested in

How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2

Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

$\log_{2}[\log_{2}(\sqrt{4x})]=1$

i.e. $\log_{2}(\sqrt{4x})=2^{1}$

i.e. $\sqrt{4x}=2^{2}$

i.e. $\sqrt{4x}=4$

i.e. $4x=4^{2}$

i.e. $4x=16$

i.e. $x=4$

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is $( 0,\infty )$ .

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0

3 years ago

Read 2 more answers

Solve the equation. Check your solution and show all your work. 2/3 h = 4

AlexFokin [52]

Answer: h=6

Step-by-step explanation:

4 0

3 years ago

Please order a b and c from least to greatest

vagabundo [1.1K]

Answer:

Jsi18 8 7

Step-by-step explanation:

Ndjsiwiw

4 0

2 years ago

HELP ITS PAST DUE I WILL PICK BRALIEST!!!! (i dont know if i spelled that right)

Contact [7]

Correct: m,b,c
incorrect: a,n,c
it’s hard to explain

8 0

2 years ago

Read 2 more answers

Find the average value of f(x+y)=sin(x+y) over

Troyanec [42]

For each given region $D$ , the average value of $f$ over $D$ is the integral of $f$ over $D$ divided by the area of $D$ . In both cases, $D$ is a rectangle so the area is trivial.

a. The area of $D$ is $\dfrac\pi3\cdot\dfrac{5\pi}3=\dfrac{5\pi^2}9$ . The integral of $f$ over $D$ is

$\displaystyle\int_0^{5\pi/3}\int_0^{\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$\displaystyle=\int_0^{5\pi/3}\left(\cos y-\cos\left(y+\dfrac\pi3\right)\right)\,\mathrm dy$

$=\sin\dfrac{5\pi}3-\sin\left(\dfrac{5\pi}3+\dfrac\pi3\right) - \sin0+\sin\dfrac\pi3=0$

So the average value of $f$ over this region is 0.

b. The area of $D$ is $\dfrac{2\pi}3\cdot\dfrac{7\pi}6=\dfrac{7\pi^2}9$ . The integral of $f$ is

$\displaystyle\int_0^{7\pi/6}\int_0^{2\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^{7\pi/6}\left(\cos y-\cos\left(y+\frac{2\pi}3\right)\right)\,\mathrm dy$

$=\sin\dfrac{7\pi}6-\sin\left(\dfrac{7\pi}6+\dfrac{2\pi}3\right) - \sin0+\sin\dfrac{2\pi}3=\dfrac{\sqrt3}2$

The average vale of $f$ over this region is then $\dfrac{\frac{\sqrt3}2}{\frac{7\pi^2}9}=\dfrac{9\sqrt3}{14\pi^2}$ .

4 0

2 years ago

What percent of 140 is 50?​

What percent of 140 is 50?