2. $1.75
3. $1.65
4. $1.05
5. $1.55
6. $1.20
7. $1.50
8. $1.29
You can Draw a segment WY connecting the centers<span> of the </span>two circles<span>, and then draw a segment, WS, so that YS + SZ = YZ and WS ⊥ YZ).</span>
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
For the first Q the answer is the first square on the left 10 miles divided by 12 hours = 0,83 miles
And the second Q goes with the last square 12 hours divided by 10 miles = 1.2 h which in minutes is 72 minutes or 1h and 12 minutes.