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3 years ago

Prove that √3cosec20° - sec20° = 4

Mathematics

1 answer:

podryga [215]3 years ago

4 0

Answer:

LHS,

√3cosec20°-sec20°

hope it helps.

<h2>stay safe healthy and happy.</h2>

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What is (1/25)^x-2/5-10=115

dalvyx [7]

1.50099254

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3 years ago

Hector spent $41.75 for 2 DVDs that cost the same amount. The sales tax on his purchase was $3.15. Hector also used a coupon for

kykrilka [37]

Given:

Amount spent on 2 DVDs = $41.75

Sales tax = $3.15

Coupon = $1.00 off

To find:

The cost of each DVD.

Solution:

Let x be the cost of each DVD.

Then, cost of two DVDs = 2x

Amount spent of 2 DVDs = Cost of 2 DVDs + Sales tax - Coupon discount

$41.75=2x+3.15-1.00$

$41.75=2x+2.15$

$41.75-2.15=2x$

$39.6=2x$

Divide both sides by 2.

$\dfrac{39.6}{2}=x$

$19.8=x$

Therefore, the cost of each DVD is $19.8.

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3 years ago

Julien was involved in an accident in which he merged into another car, damaging the front fender of the other car. Julien is fu

Irina-Kira [14]

Answer:

Collision coverage pays for damage to your car resulting from a collision with another car, an object, such as a tree or telephone pole, or as a result of flipping over (note that collisions with deer are covered under comprehensive). It also covers damage caused by potholes.

Hope this helped. :)

4 0

3 years ago

What is the point called where the perpendicular bisectors of the sides of a triangle intersect

Vikki [24]

Answer: Circumcenter

This is the center of the circle that goes through the three vertices of the triangle. This circle is known as the circumcircle. It is the smallest circle possible in which the circle encompasses the triangle and none of the triangle spills outside the circle.

6 0

3 years ago

WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINLIEST!!

gizmo_the_mogwai [7]

Answer:

Area = 342 $cm^2$ , Perimeter = 22.79 cm

Step-by-step explanation:

First, divide the shape into 3:

An arc, a square, and a triangle.

Dimensions of shapes:

Arc:

Degree = 40°

Arms = 4 cm

Square:

All sides are 4 cm

Triangle:

base = 3 cm

height = 4 cm

hypotenuse = 5 cm

To get perimeter:

Arc length = $\frac{40}{360} * (2*\pi * (4))$ (4 is the arm length ) = 2.7925 cm

Arc arm = 4 cm

Square sides (only two are outside) = 2 * 4 = 8 cm

Triangle (only hypotenuse and base are outside) = 5 + 3 = 8 cm

So total perimeter is 2.7925 + 4 + 8 + 8 = 22.79cm

To get area:

Arc area (the pizza shape) = $\frac{40}{2\pi } * \pi * (4)^{2}$ (4 is the arm length) = 320 $cm^{2}$

Square area = side * side = 4 * 4 = 16 $cm^{2}$

Triangle = (1/2) * base* height = (1/2) * 3 * 4 = 6 $cm^{2}$

So total area is 320 + 16 + 6 = 342 $cm^2$

3 0

3 years ago

Read 2 more answers

Prove that √3cosec20° - sec20° = 4​

Prove that √3cosec20° - sec20° = 4