Let theta = A... Since I got no theta in my phone's keyboard
CotA /cosAsecA
Buh we all know cotA=1/tanA.....which can also be rewritten as cosA/sinA.... (thus the reciprocative Form of sinA/cosA)
SecA=1/cosA
Therefore
1/tanA ÷cosAx1/cosA
1/tanA ÷cosA/cosA
CosA/cosA=1
1/tan A÷1
Hence =cosA/sinA
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Answer:
∠A = ∠C = 60°
∠B = ∠D = 120°
Step-by-step explanation:
In quad. DPBQ, by angle sum property we have
∠PDQ + ∠DPB + ∠B + ∠BQD = 360°
60° + 90° + ∠B + 90° = 360°
∠B = 360° – 240°
Therefore, ∠B = 120°
But ∠B = ∠D = 120° opposite angles of parallelogram
As, AB || CD opposite sides of a parallelogram
∠B + ∠C = 180° sum of adjacent interior angles is 180°
120° + ∠C = 180°
∠C = 180° – 120° = 60°
Hence ∠A = ∠C = 60° Opposite angles of parallelogram are equal
Answer: 49.12 ft²
Step-by-step explanation:
To find the area of this figure, we can separate it into 2 parts. We can find the area of the semi circle and the area of the triangle. Then we add together to areas.
Area of Triangle
A=bh/2
A=6(8)/2
A=48/2
A= 24 ft²
Area of Semi Circle
A=πr²/2 (Divide by 2 because semi circle is half of a circle, so we divide the area by 2)
A=π(4)²/2
A=(3.14)(16)/2
A=25.12 ft²
Total area
A=24+25.12=49.12 ft²
Answer:
It's A hope i helped
Step-by-step explanation: