Ask question

Ask question

All categories

Genrish500 [490]

2 years ago

7

You are working as an office apprentice for the bksb Newcastle Arena. You are helping collect a customer satisfaction survey for

the arena. Enter the following replies into the table below.

1 answer:

Nana76 [90]2 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

What is the equation of a line that has a slope of 0 and goes through the point (4, 10)?

kompoz [17]

Answer:

y =10

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Given

m = 0 and (x0, y0) = (4, 10)

On substituting;

y - 10 = 0(x-4)

y - 10 = 0

y = 0+10

y = 10

Hence the required equation of the line is y =10

4 0

3 years ago

Change the following fractions into mixed numbers

Travka [436]

A) 23/8 divide 23 by 8 to get 2 with remainder 7 therefore 2 7/8
work all by treating each fraction as a division problem and placing the remainder over the divisor
b) 14/3 = 4 2/3
c) 19/11 = 1 8/11
d) 8/7 = 1 1/7
e) 17/9 = 1 8/9
f) 27/8 = 3 3/8
g) 35/5 = 11 2/3
h) 9/4 = 2 1/4

6 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$ is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4}$

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0

2 years ago

Share $600 between Anna and Raman in the ratio 3:7 and 1:4

Ulleksa [173]

Answer:

3 : 7 =>

Anna = $180

Raman = $420

1 : 4 =>

Anna = $120

Raman = $480

Step-by-step explanation:

<u>Shares when ratio is 3 : 7</u>

Anna : Raman = 3 : 7

Sum of ratio 10

Anna's share=

$\frac{3}{10} \times 600 = \$ 180$

Raman 's share=

$\frac{7}{10} \times 600 = \$ 420$

<u>Shares when ratio is 1 : 4</u>

Anna : Raman = 1 : 4

Sum of ratio = 5

Anna 's share =

$\frac{1}{5} \times 600 = \$ 120$

Raman's share =

$\frac{4}{5} \times 600 = \$ 480$

8 0

3 years ago

How to solve Slope Intercept Form equations?

klasskru [66]

I can help! Do you have an example problem that I can show you step by step?

5 0

3 years ago