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Anna35 [415]
3 years ago
8

What is the value of the underlined digit 65

Mathematics
2 answers:
aalyn [17]3 years ago
8 0
The value is the tens place
True [87]3 years ago
6 0

No se como aserlo es para ayudar a mi hija

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On average, Christopher scores 2 goals in a soccer game but, depending on how well the opposing team is playing, his goal total
SVETLANKA909090 [29]

Given:

Christopher scores 2 goals in a soccer game.

His goal total can vary from the average by 1 goal.

To find:

The absolute value equation can be used to calculate Christopher's maximum and minimum goals per game.

Solution:

Let Christopher scores x goals in a soccer game.

Then difference between actual goals and average goals is x-2.

His goal total can vary from the average by 1 goal.

Maximum number of goals = 2+1 = 3

Minimum number of goals = 2-1 = 1

It means, the difference between actual goals and average goals is either -1 and 1.

x-2=-1        ...(1)

x-2=1         ...(2)

Using (1) and (2),we get

|x-2|=1

Therefore, the correct option is C.

7 0
3 years ago
Solve for t. 3t 35=6
zhenek [66]

The answers 9. I took the test :)


3 0
3 years ago
Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
2 years ago
PLEASE HELP ME !!!!!
Nuetrik [128]
I would say A. I hope I am right. I dunno if it would be A. or C.  But I think A would be the better pick.
4 0
2 years ago
I need help ASAP. What are vertices? What makes a polygon irregular? I'm so confused! How on earth do I solve these?
baherus [9]
1b.regular polygon
2b.regular octagon

& in the bottom is ....
3a.rectangle
3b.trapezoid
3c.square
3 0
3 years ago
Read 2 more answers
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