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2 years ago

The amount a worker is paid in his entire career

Mathematics

1 answer:

mihalych1998 [28]2 years ago

7 0

It might be Annual salary?

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Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

2 years ago

In the figure below, AB is a diameter of circle P.

salantis [7]

Answer:

( 41° * π * radius) / 180

Step-by-step explanation:

The arc measure of major arc ABC on circle P is

( 41° * π * radius) / 180 degrees.

For instance if P = 5 then see the picture, the Arc Length = 3.58

3 0

2 years ago

What is the solution set?<br><br> A.) (0, -2)<br> B.) (2, 0)<br> C.) (7, 0)<br> D.) (5, 3)

max2010maxim [7]

Answer:

D.) (5, 3)

Step-by-step explanation:

Solution is where two lines intersect

Both lines intersect at x = 5 and y = 3

Answer

D.) (5, 3)

8 0

2 years ago

As a first step in solving the system shown, Yumiko multiplies both sides of the equation 2x – 3y = 12 by 6. By what factor shou

GenaCL600 [577]

Answer:

Yumiko should multiply the other equation by 3.

If she adds the two equations she would be left with the variable 'x'.

Step-by-step explanation:

Given the two equations are as follows:

$2x - 3y = 12 \hspace{5mm} \hdots (1)$

$5x + 6y = 18 \hspace{5mm} \hdots (2)$

It is given that she multiplies the first equation by 6. Therefore, (1) becomes

$12x - 18y = 72 \hspace{15mm} \hdots (a)$

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.

The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.

Therefore, Equation (2) becomes:

$15x + 18y = 54 \hspace{5mm} \hdots (b)$