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Lelu [443]
3 years ago
13

Metro cable tv tuvo ventas de 2500000 en su primer año de funcionamiento. Si a partir de entonces las ventas aumentaron 12% con

respecto al año anterior, calcule las ventas de la empresa en el quinto año y las ventas totales durante los primeros 5 años de operación
Mathematics
1 answer:
never [62]3 years ago
4 0

Explicación paso a paso:

Dado

Principal = 2,500,000

Tasa = 12% (anual)

tiempo = 5 años

Incremento después del primer año = 12% de 2.500.000

= 12/100 * 2,500,000

= 12 * 25000

= 300.000

El monto al final de los 5 años se calculará utilizando la fórmula de interés compuesto;

A = P (1 + r) ^ n

A = 2500000 (1 + 0,12) ^ 5

A = 2500000 (1,12) ^ 5

A = 2500000 (1,7623)

A = 4.405.854,208

<em><u>Por lo tanto, las ventas totales durante los primeros 5 años de operación son 4.405.854,208 </u></em>

<em><u> </u></em>

Obtenga la cantidad obtenida en el quinto año

El monto al final de los 4 años se calculará utilizando la fórmula de interés compuesto;

A = P (1 + r) ^ n

A = 2500000 (1 + 0,12) ^ 4

A = 2500000 (1,12) ^ 4

A = 2500000 (1,5735)

A = 3.933.798,4

Utilidad obtenida en el quinto año = 4.405.854,208 - 3.933.798,4

A = 4.405.854,208 - 3.933.798,4

A = 472.055,808

Por lo tanto, la ganancia obtenida en el quinto año es de 472,055.808

Monto realizado en el quinto año = Principal + intereses en el quinto año

Monto realizado en el quinto año = 2500000 + 472,055.808

<u><em>Monto realizado en el quinto año = 2,972,055.808</em></u>

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Answer:

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Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

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                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

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Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

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