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3 years ago

Suppose that g(x) = f(x - 2) +7. Which statement best compares the graph of

Mathematics

1 answer:

sweet [91]3 years ago

6 0

Answer:

Step-by-step explanation:

changing the number in the f(x) will shift right and left ( + for left and - for right ) and changing out f(x) will shift up and down ( + for up and - for down)

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Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

I will mark you

Nana76 [90]

Answer:

Yes, because the x's do not have more than one y.

Step-by-step explanation:

x y

0 0

5 10

6 12

10 20

(That's meant to be a table). Looking at the x and y table values, you can see that none of the x's have two y's. So, this relation is a function.

7 0

3 years ago

HELP QUICK!!!!!!!!!!

Mama L [17]

Answer:

Option is right

Step-by-step explanation:

Given that bella want to know what the students at her school think of her show. which is the BEST group to survey to find this information

For getting accurate results she must select a random sample without bias

For this option a will not serve since she selects only students she recognizes.

Option B may not be right, as during show on the face they may not give correct opinion

C is right as a random sample is taken

D is wrong as the first 30 students may not be at random.

So option C is right

8 0

3 years ago

Read 2 more answers

Which numerical expression reprensents 1/2 the sum of 7 and 5 ?

Amiraneli [1.4K]

You need to multiple 7 and 5 or you could just skip the answer

3 0

3 years ago

Read 2 more answers

What is the answer for: 7 - 8(x-3)=x-14

ikadub [295]

Answer:

1. x=5

2.x=-33/8

3.x=10

4.x=5

Step-by-step explanation:

5 0

2 years ago