Associative property of addition
Given
Expenditures at Manager's Store; expenditures at Competitor's Store.
Find
a) average spent at each store
b) which store is better represented by the mean value
c) an explanation for the answer in ≥ 2 sentences
Solution
a) The sum of expenditures divided by the number of expenditures (15) is ...
... average for Manager's Store: $37.60
... average for Competitor's Store: $48.53
b) The expenditures at Manager's Store are well-represented by the mean (average).
c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.
Answer:
(47+37)(47-37)
Step-by-step explanation:
47^2-37^2 is a difference of two squares. a^2-b^2 = (a+b)(a-b) so this expression can be factored to (47+37)(47-37) = (84)(10) = 840
AB = √(5-0)^2 + (4-0)^2 = √25+16 = √41
BC = √(0-5)^2 + (8-4)^2 = √25+16 = √41
CD = √(-5 - 0)^2 + (4-8)^2 = √25+16 = √41
AD = √(-5-0)^2 + (4-0)^2 = √25+16 = √41
All the sides are equal so it is either a square or a rhombus.
The distance from A to C on the x axis is: 8-0 = 8 units.
The distance from B to D on the Y axis is: 5 - - 5 = 10 units.
Because the two distances are not the same, it is not a square.
The answer is 4. AB=BC ; therefore, ABCD is a rhombus.
I'm assuming you're supposed to find the chance of them drawing red or blue/
So the whole is 20, and red and blue combined is 14.So its 14/20, which is 70%, and as a simplified fraction it is 7/10.
