Karen is moving at 81.2 miles per hour while Melinda is moving at 71.2 miles per hour.
<h3>Equation for
speed</h3>
Speed is the ratio of total distance travelled to total time taken. It is given by:
Speed = distance / time
Let a represent Karen speed and b represent Melinda speed, hence:
a = b + 10
a - b = 10 (1)
Also:
a = d₁ / 1
d₁ = a
b = d₂/ 1 hour
d₂ = b
Since they are 108 miles apart, using Pythagoras:
108² = d₁² + d₂²
a² + b² = 11664
(b + 10)² + b² = 11664
b = 71.2 mph, a = 81.2 mph
Karen is moving at 81.2 miles per hour while Melinda is moving at 71.2 miles per hour.
Find out more on speed at: brainly.com/question/4931057
2 to the 12th power should be correct
Answer:
Step-by-step explanation:
We'll take this step by step. The equation is
![8-3\sqrt[5]{x^3}=-7](https://tex.z-dn.net/?f=8-3%5Csqrt%5B5%5D%7Bx%5E3%7D%3D-7)
Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:
![-3\sqrt[5]{x^3}=-15](https://tex.z-dn.net/?f=-3%5Csqrt%5B5%5D%7Bx%5E3%7D%3D-15)
The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:
![\sqrt[5]{x^3}=5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%3D5)
Let's rewrite that radical into exponential form:

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:
![x=\sqrt[3]{5^5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E5%7D)
Let's group that radicad into groups of 3's now to make the simplifying easier:
because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:
which is the same as:
![x=5\sqrt[3]{25}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B25%7D)
The number 100 -> that has 2 zeros
Is the same as 10^2 as for this simplified is equal to 100.
100=100
They are the same. They have the same number of zeros.