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jeka57 [31]
3 years ago
9

If Sally has 2 apples a Jeremy has 9 apples how did they get 24?

Mathematics
1 answer:
Elza [17]3 years ago
6 0
They bought more apples
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Given: △DKS, m∠K = 90°<br> Find: m∠DOS
Bas_tet [7]

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135

Step-by-step explanation:

if mK is 90 then mD is 60 and mS is 30. since the new point is in the middle of the triangle divide 60 and 30 by 2. Now mD is 30 and Ms is 15 so 30+15=45 so 180-45=135

5 0
4 years ago
I'm confused........​
defon

Answer: Yeah me to

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Find the area under the standard normal distribution curve between z = –2.05 and z = 2.05.
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\mathbb P(-2.05
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3 years ago
Eli buys milk and lemons at the store.
aniked [119]

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$6.32

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6 0
3 years ago
PLS HELP WILL MARK BRAINLIEST!!!!!!!!<br> answer both questions (they are two separate questions)
Angelina_Jolie [31]

<u>Answer A is correct for both questions.</u>

Step-by-step explanation:

The area of the rectangle is lengthxwidth. To find the length, we can divide the area by the width.

\frac{(4x^2-43x+63)}{(4x-7)} is the equation.

We need to simplify it (or just divide). Since the coefficient of the area (on the x^2) is the same as that on the width, we know that that same coefficient on the length is 1.

This gets us to the basic frame (1x+/-y).

To find the value of y, we need to pay attention to the "-43x+63" and "-7" aspects of the area and width, respectively. To get "63," the "-7" was multiplied by the y — by dividing 63 by -7, we know that the value of y is -9 (the numbers both have to be negative to multiply to a positive number).

We are left with the length (x-9). Put together, this means (x-9)(4x-7) is the area. Multiplying, that makes (4x^2-7x-36x+63), or (4x^2-43x+63). Since this is the area given to us, we know our answer is correct. For this question, the answer is A.

*****

Divide 9x^4-2-6x-x^2 by 3x-1. First, put the first equation in order by exponents. We get \frac{9x^4-x^2-6x-2}{3x-1}. Since the exponent on the upper equation goes up to x^4, and we are dividing by a simple x, we know that the first exponent in our answer will be x^3. Since our coefficient needs to have a product of 9 when multiplied by 3, it is 3. The first part of our answer is (3x^3). Since there is no exponent of 3 for x in the upper equation, and since the "x^2" that has to be the next term in the equation due to it being present in each answer choice, we know that it as to be a "+x^2" — the "3x^3 that result from the "-1" (in the lower equation) being multiplied by 3x^3 have to be cancelled out by a "-3x^3", and if the sign for the term "x^2" is negative, we end up with tw0 "3x^3" that add up to "6x^3" instead of cancelling each other out.

Now, we have (3x^3-x^2). We can immediately rule out C. Moving on.

We now have (3x-1)(3x^3+x^2)=9x^4-x^2. We can rule out answer choice B because it is incomplete - we are missing the second part of the upper equation, "-6x-2." Both of the remaining answers include "-2" as the next term, whether with an x or without.

<u><em>Honestly, I haven't done algebra in a few years — while I know there's a way to deduce the rest of the equation, let's solve the equation using the two remaining answer choices and see which one is correct.</em></u>

A: (3x-1)(3x^3+x^2-2-\frac{4}{3x-1} )

=9x^4+3x^3-6x -3x^3-x^2+2-4 <u>(FOIL) (3x-1 times </u>-\frac{4}{3x-1}<u> = -4)</u>

=9x^4+3x^3-3x^3-x^2-6x+2-4  <u>(in order of exponents)</u>

=9x^4-x^2-6x+2-4 (simplify)

=9x^4-x^2-6x-2 (simplify)

<u />

D: (3x-1)(3x^3+x^2-2x-\frac{4}{3x-1} )

=9x^4+3x^3-6x^2-\frac{4}{1} -3x^3-x^2+3x+\frac{4}{1}(FOIL)

=9x^4+3x^3-3x^3-7x^2-4+4 (in order of exponents)

=9x^4-7x^2 (simplify)

A is exactly the long fraction we started with (9x^4-2-6x-x^2), just in a different order! This means that answer A, when multiplied by (3x-1), equals the same thing which, if divided by (3x-1), yields answer A. Because of the rules of multiplication/division (xy=z, z/x=y, z/y=z), this means that we have the proper set of numbers. Answer A is correct.

I hope this helps!!!!! Let me know if there's anything else I can help with :)

5 0
2 years ago
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