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Natasha2012 [34]

3 years ago

7

HELP !!

1 answer:

vesna_86 [32]3 years ago

3 0

Answer:

c

Explanation:

because air have the fastest speed

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What is the significant figure of 0.00000006

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3 years ago

The bending of waves due to a change in speed is called

kozerog [31]

That's "refraction".

8 0

3 years ago

A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the partic

olga_2 [115]

Answer:

The speed v of the particle at t=5.00 seconds = 43 m/s

Explanation:

Given :

mass m = 5.00 kg

force f(t) = 6.00t2−4.00t+3.00 N

time t between t=0.00 seconds and t=5.00 seconds

From mathematical expression of Newton's second law;

Force = mass (m) x acceleration (a)

F = ma

$a = \frac{F}{m}$ ...... (1)

acceleration (a) $= \frac{dv}{dt}$ ......(2)

substituting (2) into (1)

Hence, F $= \frac{mdv}{dt}$

$\frac{dv}{dt} = \frac{F}{m}$

$dv = \frac{F}{m} dt$

$dv = \frac{1}{m}Fdt$

Integrating both sides

$\int\limits {} \, dv = \frac{1}{m} \int\limits {F(t)} \, dt$

The force is acting on the particle between t=0.00 seconds and t=5.00 seconds;

$v = \frac{1}{m} \int\limits^5_0 {F(t)} \, dt$ ......(3)

Substituting the mass (m) =5.00 kg of the particle, equation of the varying force f(t)=6.00t2−4.00t+3.00 and calculating speed at t = 5.00seconds into (3):

$v = \frac{1}{5} \int\limits^5_0 {(6t^{2} - 4t + 3)} \, dt$

$v = \frac{1}{5} |\frac{6t^{3} }{3} - \frac{4t^{2} }{2} + 3t |^{5}_{0}$

$v = \frac{1}{5} |(\frac{6(5)^{3} }{3} - \frac{4(5)^{2} }{2} + 3(5)) - 0|$

$v = \frac{1}{5} |\frac{6(125)}{3} - \frac{4(25)}{2} + 15 |$

$v = \frac{1}{5} |\frac{750}{3} - \frac{100}{2} + 15 |$

$v = \frac{1}{5} | 250 - 50 + 15 |$

$v = \frac{215}{5}$

v = 43 meters per second

The speed v of the particle at t=5.00 seconds = 43 m/s

6 0

3 years ago

Can u answer 4 and 5 for me

Luda [366]

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8 0

4 years ago

The rms current output in a circuit is 7.75 A. What is the maximum current?

Andru [333]

The maximum current in an ac circuit is related to the rms current by:
$I_{rms} = \frac{I_0}{ \sqrt{2} }$
where $I_{rms}$ is the rms current and $I_0$ is the maximum current.

If we re-arrange the formula and we use $I_{rms}=7.75 A$ , we can find the value of the maximum current:
$I_0 = \sqrt{2} I_{rms} = \sqrt{2}(7.75 A)=11.0 A$

5 0

3 years ago