mercury??????? my only guess
The net force on the charge at the origin is -1.2×10-8
<u>Explanation:</u>
Solving the problem,
- Draw the x-axis and the locations of the given three charges.
- The forces applied on the charge at the origin and there are two of them, and since all the changes are positive, all the forces are repulsive.
- we have the formula, F = kq1Q/r².
- F1 = kq1Q/r²1 = (9.0*109Nm²/C²)(2.2*10^-9C)(3.5*10^-9C)/(1.5m)² = 31*10-9N = 3.1*10-8N. F1 points to the right (+x direction).
- F2 = kq2Q/r²2 = (9.0*109Nm²/C²)(5.4*10^-9C)(3.5*10^-9C)/(2.0m)² = 43*10^-9N = 4.3*10^-8N.
- F2 points to the left (-x direction).
- To find the net force we have to subtract the force F1 and force F2 .
- The net force is F(origin) = F1 - F2 = -1.2×10-8N.
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Answer:
the answer for this is my.
When the electric field pierces outward through the section.
Calcium chloride contains ionic bonds.
Pennies contain metallic bonds.
Hydrochloric acid contains covalent bonds.
You're welcome.
