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Arte-miy333 [17]
3 years ago
11

A child is on a playground swing, motionless at the highest point of his arc. what energy transformation takes place as he swing

s back down to the lowest point of his motion?
A) K--> Ug
B) Ug--> K
C) Eth--> K
D) Ug-->Eth
E) K--> Eth
Physics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:

option B

Explanation:

The correct answer is option B

When the playground swing reaches the highest point the swing has high potential energy.

When the swing is at the bottom kinetic energy of the swing is maximum.

When the swing back down the potential energy at the top point of the swing is converted to the Kinetic energy.

so,           U g --> K

      Ug is the potential energy of the swing

      K is the kinetic energy of the swing.

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Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

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Answer:

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Explanation:

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5 0
3 years ago
The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o
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Answer:

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Explanation:

we know,

Y=Ae^{-kt}

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Y(0) = A

given that half life of plutonium 239 = 24,200

\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}

Y=Ae^{-kt}

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