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3 years ago

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Applicants for the University of Statland take two tests, one for writing ability and the other on critical thinking, and normal

ised scores are recorded on each between 0 and 1. For a given applicant, let XX be the score on the writing test and YY the score on the critical thinking test. A model for the joint probability density function for the two test scores can be taken as:

1 answer:

bezimeni [28]3 years ago

7 0

Answer:

hello your question is incomplete attached below is the complete question

<em>answer</em> : 1

Step-by-step explanation:

Given Function:

F(x,y)= $\left \{ {{1/4(2x+y)} \atop {0}} \right.$ for 0<x<1, 0<y<2

elsewhere.

Evaluating the marginal density of the writing test score at point

X = 1/2 = 1/4 ( 4x + 2 ) = 1/4 ( 4 * 1/2 + 2 ) = 1

attached below is the detailed solution

You might be interested in

A tattoo enthusiast website claims that :

KATRIN_1 [288]

Answer:

The probability that a person is a Millennial given that they have tattoos is 0.5069 (50.69%) or about 0.51 (51%).

Step-by-step explanation:

We have here a case where we need to use Bayes' Theorem and all conditional probabilities related. Roughly speaking, a conditional probability is a kind of probability where an event determines the occurrence of another event. Mathematically:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

In the case of the Bayes' Theorem, we have also a conditional probability where one event is the sum of different probabilities.

We have a series of different probabilities that we have to distinguish one from the others:

The probability that a person has a tattoo assuming that is a Millennial is:

$\\ P(T|M) = 0.47$

The probability that a person has a tattoo assuming that is of Generation X is:

$\\ P(T|X) = 0.36$

The probability that a person has a tattoo assuming that is of Boomers is:

$\\ P(T|B) = 0.13$

The probability of being of Millennials is:

$\\ P(M) = 0.22$

The probability of being of Generation X is:

$\\ P(X) = 0.20$

The probability of being of Boomers is:

$\\ P(B) = 0.22$

Therefore, the probability of the event of having a tattoo P(T) is:

$\\ P(T) = P(T|M)*P(M) + P(T|X)*P(X) + P(T|B)*P(B)$

$\\ P(T) = 0.47*0.22 + 0.36*0.20 + 0.13*0.22$

$\\ P(T) = 0.204$

For non-independent events that happen at the same time, we can say that the probability of occurring simultaneously is:

$\\ P(M \cap T) = P(M|T)*P(T)$

Or

$\\ P(T \cap M) = P(T|M)*P(M)$

But

$\\ P(M \cap T) = P(T \cap M)$

Then

$\\ P(M|T)*P(T) = P(T|M)*P(M)$

We are asked for the probability that a person is a Millennial given or assuming that they have tattoos or P(M | T). Solving the previous formula for the latter:

$\\ P(M|T)*P(T) = P(T|M)*P(M)$

$\\ P(M|T) = \frac{P(T|M)*P(M)}{P(T)}$

We have already know that

$\\ P(T|M) = 0.47\;P(M) = 0.22\;and\;P(T) = 0.204$ .

Therefore

$\\ P(M|T) = \frac{0.47*0.22}{0.204}$

$\\ P(M|T) = 0.50686 \approx 0.51$

Thus, the probability that a person is a Millennial given that they have tattoos is 0.5069 (50.69%) or about 0.51 (51%).

5 0

4 years ago

Please help me in this one

ANEK [815]

The best choices are table 1.

All the input values are being multiplied by themselves by the output values.

This creates a congruent and linear correlation and congruence.

I hope this helps!

Brainliest answer is always appreciated!

8 0

4 years ago

About 13 out of 20 homes have a personal computer. On a street with 60 homes, how many would you expect to have a personal compu

Aleks04 [339]

This can be solved using a ratio. The ratio is: 13/20=x/60 this would then become 20x= 780 divide both sides by 20 and you get x=39. the answer is 39

5 0

4 years ago

Read 2 more answers

I, myself self am not too good at Sin, Con, and Tan so I could use some help on double-checking if this is correct??

alex41 [277]

Answer:

$\tan(a) = \frac{28}{45}$

look from the tan A angle , the opposite is 28 and adjacent is 45

4 0

3 years ago

An estimated 40% of all people were born after the year 2000. If two people are selected at random from around the world, what a

sukhopar [10]

The chances that NEITHER of these two selected people were born after the year 2000 is 0.36

<h3>How to determine the probability?</h3>

The given parameters are:

Year = 2000

Proportion of people born after 2000, p = 40%

Sample size = 2

The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:

P = (1- p)^2

Substitute the known values in the above equation

P = (1 - 40%)^2

Evaluate the exponent

P = 0.36

Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36

Read more about probability at

brainly.com/question/25870256

#SPJ1

4 0

1 year ago