the difference is 55 and that's the answer to that math problem
Answer:
Find the relative frequency for the event "heads" for each friend:
Friend 1: 0.59 (41/70)
Friend 2: 0.7 (49/70)
Friend 3: 0.37 (26/70)
If the friends combine their results to get 116 heads and 94 tails, what is the relative frequency for the event "heads"?
0.55 (116/210)
Suppose each friend flips a coin 700 times. Is there a value you would expect the relative frequency for the event "heads" to be close to?
For Friend 1, basing it off the 0.59 frequency from earlier, I would expect the heads to be around 413.
Friend 2, 490
Friend 3, 259
Answer:
38
Step-by-step explanation:
To find the value of f(6), we substitute the value 6 where x is into the function. You would get:
7(6) - 4
42 - 4
f(6) = 38
Hello!
She placed 6 ribbons
2 at the ends and 5 every 3 meters
Hey!
This could be rewritten as:
2x + 1 + 5x
We can add like terms together:
7x + 1