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Ksju [112]
3 years ago
7

Which expression means “ multiply 3 by the sum of m and p “

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0
The answer would be A. hope this helps
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On a certain​ river, a paddleboat travels 12 miles upstream ​(against the​ current) in the same amount of time it travels 20 mil
marin [14]

Given :

a paddle boat travels  upstream = 12 miles

a paddle boat travels  downstream = 20 miles

speed of the current = 2 miles per ​hour

Let the speed of the boat =x

Let the time taken = t

We know the distance for upstream D= (boat speed - current speed) * time

the distance for downstream D= (boat speed + current speed) * time

Plug in all the values and variables in the distance

For upstream 12 = (x-2)t, then t = \frac{12}{x-2}

For downstream 20 = (x+2)t then t = \frac{20}{x+2}

we got two equations for t, equate it and solve for x

\frac{12}{x-2} = \frac{20}{x+2}

Cross multiply it

12(x+2) = 20(x-2)

12x + 24 = 20x - 40 (subtract 12x  and add 40 on both sides)

64 = 8x

x= 8

the speed of the boat in still water = 8 miles per hour



3 0
3 years ago
Read 2 more answers
If x =30 when y= -15 find x when y is 3
lawyer [7]
48 is the answer my friend. x is 45 more than y. 3+45 is 48
7 0
3 years ago
X2+ y2 − 8x + 12y + 27 = 0
snow_lady [41]

Central (4,–6)

Radius 5

3 0
3 years ago
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Jill bought a pound of strawberries for $4.00. What is the price, in dollars, per ounce of strawberries? (1lb = 16 oz)
kvv77 [185]
4/16=.25
$0.25/oz
Each ounce is 25 cents. Multiply .25 by 16 and you get 4.
8 0
3 years ago
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80. You buy a new car for $24,000. At the end of n years, the value of your car is given by the sequence: an=24000(3/4)n, n=1, 2
kipiarov [429]

Answer:

The value at the end of the fifth year (a5) is equal to $5,696.

As the number of years n is the exponent of a number that is smaller than 1, the value of the car is decreasing with the years.

We also can conclude that the value of the car decreases 25% each year.

Step-by-step explanation:

The value of the car is represented by an=24000(3/4)^n, where n is the year.

The value at the end of the fifth year (a5) is equal to:

a_5=24,000\left(\dfrac{3}{4}\right)^5=24,000*0.2373=5,695

As the number of years n is the exponent of a number that is smaller than 1, the value of the car is decreasing with the years.

We also can conclude that the value of the car decreases 25% each year:

a_n/a_{n-1}=(3/4)^{n-(n-1)}=(3/4)^1=0.75

4 0
3 years ago
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