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Ksju [112]
3 years ago
7

Which expression means “ multiply 3 by the sum of m and p “

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0
The answer would be A. hope this helps
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Find the median.<br> 2, 20, 19, 15, 11,9,7,1<br> OA. 10<br> OB.<br> 10.5<br> c. 19<br> D. 20
pickupchik [31]

Answer:

A. 10

Step-by-step explanation:

First put the numbers in order from least to greatest then find the two numbers in the center of that since there is an even number of numbers there will be two the add and divide by two and you get 10.

1,2,7,9,11,15,19,20

9+11=20

20/2=10

3 0
3 years ago
Read 2 more answers
I need help pleeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeaseeeeee
UkoKoshka [18]

Answer:

3 option is correct

Step-by-step explanation:

because all the domains and ranges calculation matches in eqn 3

3 0
3 years ago
What is unsustainable commercial​
lozanna [386]
Unsustainable commercial is not fair for you
3 0
3 years ago
PLZ HELP ME, DUE RN!!
mash [69]

Answer:

Step-by-step explanation:

For us to determine the friends that live exactly halfway between any two other friends, we need to determine the midpoint of any two of the coordinates and check whether the coordinate gotten is any of other people coordinates.

Using the coordinates B (22,5)  and Ju (4,5), Using the mid point formula;

m(X,Y) = (\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})\\

X = \frac{x_2+x_1}{2}

X = \frac{22+4}{2}

X = \frac{26}{2}\\ X = 13

Y =\frac{y_2+y_1}{2}\\Y = \frac{5+5}{2}\\Y = \frac{10}{2}\\Y = 5

(X, Y) = (13, 5)

Hence the friend that live half way of B (22,5)  and Ju (4,5) is J(13, 5)

Similarly as above, using the coordinates of M (11,5) and A  (31,5)

X = (11+31)/2

X = 42/2

X = 21

Y = (5+5)/2

Y = 10/2

Y = 5

Midpoint of both friends is (21, 5)

Hence the friend that live half way of M (11,5)  and A (31,5) is Ma(21, 5)

Also, using the coordinates of J (13,5)  and A  (31,5)

X = (13+31)/2

X = 44/2

X = 22

Y = (5+5)/2

Y = 10/2

Y = 5

Midpoint of both friends J and A is (22, 5)

Hence the friend that live half way of J (13,5)  and A (31,5) is B(21, 5)

4 0
3 years ago
A bag of chocolate mix weighed 1/4 of a kilogram could make enough brownies to feed 1/7 of the students at school how many bags
Hoochie [10]
A "whole" will be 7/7, or just 1 whole.

so we know one bag can do 1/7 of all students, how many will it be needed to do 7/7?

well, in 7/7 there are seven 7/7, so, 7 bags then, or one could say,

\bf \begin{array}{ccll}&#10;\stackrel{chocolate}{bag}&\stackrel{fraction}{students}\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;1&\frac{1}{7}\\\\&#10;x&\frac{7}{7}&#10;\end{array}\implies \cfrac{1}{x}=\cfrac{\quad \frac{1}{7}\quad }{\frac{7}{7}}\implies \cfrac{1}{x}=\cfrac{1}{7}\cdot \cfrac{7}{7}&#10;\\\\\\&#10;\cfrac{1}{x}=\cfrac{1}{7}\implies 7=x
5 0
3 years ago
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