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Andrew [12]
3 years ago
15

Select the correct answer. Which set of coordinates satisfies the equations 3x-2y= 15 and 4x - y = 207 OA (2-7) OB (1.6) OC (5.0

) OD. (0,75).​

Mathematics
1 answer:
MissTica3 years ago
6 0

Answer:

C.) (5,0)

Step-by-step explanation:

You see where the lines cross together. That will be the answer.

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Describe in words the rule to calculate the area of a rhombus based on its<br> diagonals.
coldgirl [10]

Answer:

area of rhombus = 1/2 d^{1} d^{2}

half * diagonal 1 * diagonal 2 is the area of rhombus.

hope this answer helps you...

please mark as brianliest.. thank you!

6 0
3 years ago
Bacteria usually reproduce by a process called binary fission. In this type of reproduction, one bacterium divides to
Fed [463]

Answer:

\large \boxed{\text{0.0462 min}^{-1}}

Step-by-step explanation:

One formula for the reproduction of bacteria is

\dfrac{N}{N_{0}} = e^{kt}

Data:

N = 2

N₀ = 1

  t = 15 min

Calculation:

\begin{array}{rcl}\dfrac{N}{N_{0}}& =& e^{kt}\\\\\dfrac{2}{1}& = & e^{k\times15 \text{ min}}\\\\2 & = & e^{15k \text{ min}}\\\ln 2 & = & 15k \text{ min}\\k & = & \dfrac{\ln2 }{\text{15 min}}\\\\& = & \textbf{0.0462 min}^{\mathbf{-1}}\\\\\end{array}\\\text{The value of the constant k is $\large \boxed{\textbf{0.0462 min }^{\mathbf{-1}}}$}

6 0
3 years ago
In a first -aid kit the ratio of large bandages is 3 to 2. Based on this ratio, how many large bandages are in the kit if there
11Alexandr11 [23.1K]

Answer:

  48

Step-by-step explanation:

The total number of ratio units is 3+2 = 5, and the 3 ratio units representing large bandages make up 3/5 of that total. Thus, large bandages will make up 3/5 of the total number of bandages:

  3/5×80 = 48 . . . . number of large bandages in the kit

7 0
3 years ago
I need these answers
Brut [27]
I hve answered, what is your question?
4 0
3 years ago
You roll two fair dice, a green one and a red one.
olga_2 [115]

Answer:

(a) yes

(b) 1/36

(c) 1/36

(d) 1/18

Step-by-step explanation:

(a) yes they are independent as the outcome of one does not affect the outcome of the other.

(b) As the dice are fair, each possible number (1 through 6) has the same probability of being rolled.

P(1 on green die) = 1/6

P(2 on red die) = 1/6

Therefore, P(1 on green die) AND P(2 on red die) = 1/6 × 1/6 = 1/36

(c) Again, as the dice are fair, each possible number (1 through 6) has the same probability of being rolled.

P(2 on green die) = 1/6

P(1 on red die) = 1/6

Therefore, P(2 on green die) AND P(1 on red die) = 1/6 × 1/6 = 1/36

(d) p[(1 on green die and 2 on red die) OR (2 on green die and 1 on red die)

= 1/36 + 1/36

= 2/36

= 1/18

3 0
2 years ago
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