Answer:
I know this is really late but if anyone else needs help I hope this will help those people.
Step-by-step explanation: so expand (3x+5) (X-2) first apply FOIL method: (a+b) (c+d)= ac + ad +bc + bd..... a= 3x, b=5, c=x, d= -2. our end product would be 3xx+3x(-2) + 5x + 5(-2).
Then apply minus-plus rules: +(-a)= (-a)...... we would end up with 3xx-3 times 2x + 5x - 5times 2.
next simplify until we end up with 3x^2 - x- 10
Not 100% sure if this is what your looking for but this is my best educated guess from the question asked.
Answer:
No does not contain the same length
Step-by-step explanation:
Given that
A(-4,2) , B (1,4), C (2, -1)
Now
AB would be
= ![\sqrt{(1-(-4))^2 + (4-2)^2} \\\\= \sqrt{29}](https://tex.z-dn.net/?f=%5Csqrt%7B%281-%28-4%29%29%5E2%20%2B%20%284-2%29%5E2%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B29%7D)
And, BC is
![= \sqrt{(2-1)^2 + 1-(-4))^2} \\\\= \sqrt{26}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%282-1%29%5E2%20%2B%201-%28-4%29%29%5E2%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B26%7D)
As we can see that the AB and BC are not equaled
So,
AB ≠ BC
Due to the different length
Therefore they do not contains the same length
We simply applied the distance formula due to which the length could be determined and the same is to be considered
Answer:
The required confidence interval is (3.068,4.732)
Step-by-step explanation:
Consider the provided information.
He plans to use a 90% confidence interval. He surveys a random sample of 50 students. The sample mean is 3.90 alcoholic drinks per week. The sample standard deviation is 3.51 drinks and wants to construct 90% confidence interval.
Thus, n=50,
=3.90 σ=3.51
Now find degree of freedom.
![df=n-1\\df=50-1=49](https://tex.z-dn.net/?f=df%3Dn-1%5C%5Cdf%3D50-1%3D49)
The confidence level is 90% and df=49
Therefore,
![\frac{\alpha}{2} =\frac{1-0.90}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Calpha%7D%7B2%7D%20%3D%5Cfrac%7B1-0.90%7D%7B2%7D)
![\frac{\alpha}{2} =0.05](https://tex.z-dn.net/?f=%5Cfrac%7B%5Calpha%7D%7B2%7D%20%3D0.05)
Now by using t distribution table look at 49 df and alpha level on 0.05.
![t_{\frac{\alpha}{2}} = 1.67653](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%20%3D%201.67653)
Calculate SE as shown:
![SE=\frac{\sigma}{\sqrt{50} }](https://tex.z-dn.net/?f=SE%3D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B50%7D%20%7D)
![SE=\frac{3.51}{\sqrt{50}}=0.4964](https://tex.z-dn.net/?f=SE%3D%5Cfrac%7B3.51%7D%7B%5Csqrt%7B50%7D%7D%3D0.4964)
Now multiply 1.67653 with 0.4964
Therefore, the marginal error is: 1.67653 × 0.4964≈ 0.832
Now add and subtract this value in given mean to find the confidence interval.
![\bar x-E](https://tex.z-dn.net/?f=%5Cbar%20x-E%3C%5Cmu%3C%5Cbar%20x%20%2BE%5C%5C3.90-0.832%3C%5Cmu%3C3.90%2B0.832%5C%5C3.068%3C%5Cmu%3C4.732)
Hence, the required confidence interval is (3.068,4.732)
Answer:
I don't even know if what you typed is a actual question or not so I'm just gone guess it's....A or B?
Step-by-step explanation:
In math, "of" almost always means "times".
So your question is: 3/7 times (the number) = 9
Multiply each side of that equation by 7 : 3 times (the number) = 63
Divide each side by 3 : <em> The number = 21</em>