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Natali5045456 [20]

3 years ago

12

A ball is shot upward from a slingshot at a velocity of 15 m/s the height of the ball after t seconds is given by h(t)=10+ 5t+1/

4 t^2 predicted the instantaneous velocity after eight seconds

1 answer:

otez555 [7]3 years ago

3 0

Answer:

The instantaneous velocity after eight seconds is 9 m/s

Step-by-step explanation:

Given as :

The ball shot upward with velocity of 15 m/s

The height of the ball after t sec is given as h(t) = $10 + 5t + \frac{1}{4}t^{2}$

Now, The instantaneous velocity after 8 sec = $\frac{\partial h(t)}{\partial t}$

Or, The instantaneous velocity = $\frac{\partial (10 +5t + \frac{1}{4}t^{2})}{\partial t}$

or, The instantaneous velocity = $5 + \frac{1}{4}\times 2 t$

Now at t = 8 sec

The instantaneous velocity = 5 + 4 = 9 m/s

Hence The instantaneous velocity of ball at t = 8 sec , is 9 m/s Answer

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