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3 years ago

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How would it be written out though?

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ankoles [38]3 years ago

3 0

Answer:

Wait what do you mean by this?

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write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3><u>Solution:</u></h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

<em><u>The slope "m" of the line is given as:</u></em>

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$

The perpendicular bisector will run through the midpoint of the given points

So let us find the midpoint of A(-2,2) and B(5,4)

<em><u>The midpoint formula for given two points is given as:</u></em>

$\text {For two points }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right), \text { midpoint } \mathrm{m}(x, y) \text { is given as }$

$m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Substituting the given points A(-2,2) and B(5,4)

$m(x, y)=\left(\frac{-2+5}{2}, \frac{2+4}{2}\right)=\left(\frac{3}{2}, 3\right)$

Now let us find the equation of perpendicular bisector in point slope form

The perpendicular bisector passes through points (3/2, 3) and slope -7/2

<em><u>The point slope form is given as:</u></em>

$y - y_1 = m(x - x_1)$

$\text { Substitute } \mathrm{m}=\frac{-7}{2} \text { and }\left(x_{1}, y_{1}\right)=\left(\frac{3}{2}, 3\right)$

$y - 3 = \frac{-7}{2}(x - \frac{3}{2})\\\\y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

Thus the equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is found out

7 0

4 years ago

What is (f - g)(x)?<br> f(x) = -3x² - 10x<br> g(x) = x2+6x

Anastaziya [24]

Answer:

Step-by-step explanation:

-3x^2 - 10x - x^2 - 6x

-4x^2 - 16x

5 0

4 years ago

Find the area of the shape

ella [17]

Answer:

the area of the shape is 8cm

7 0

3 years ago

Read 2 more answers

Daniela painted a photo that was 4/5 afoot by 1 7/8 of afoot. What was the area?

Ahat [919]

Answer:

$\frac{3}{2}$ square feet

Step-by-step explanation:

The dimensions of the photo is 4/5 by 1 7/8 of a foot.

But,

1 7/8 = $\frac{15}{8}$ feet

So that,

length of the photo = $\frac{15}{8}$ feet

width of the photo = $\frac{4}{5}$ feet

The area of the photo = length x width

= $\frac{15}{8}$ x $\frac{4}{5}$

= $\frac{60}{40}$

= $\frac{3}{2}$

Area of the painted photo is $\frac{3}{2}$ square feet.

8 0

3 years ago

If you know the answer please help

adoni [48]

The answer is 330. 67x5=335. Now round it.

5 0

3 years ago