Simply put, 18 x 2/3 = 36/3 = 12
The horses eat 12 bales
Answer:
0, 3
Step-by-step explanation:
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:5
Step-by-step explanation:
reverse the steps
2(x+1)/3=4
2(x+1)/3×3=4×3
2(x+1)/2=12/2
x+1=6
x=6-1
x=5
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
