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2 years ago

Equivalent this problem -3(4 – 2g) – 6?

Mathematics

2 answers:

polet [3.4K]2 years ago

6 0

Answer:

-12 + 6g - 6

Step-by-step explanation:

lions [1.4K]2 years ago

5 0

Let's simplify step-by-step.
−
3
(
4
−
2
g
)
−
6
Distribute:
=
(
−
3
)
(
4
)
+
(
−
3
)
(
−
2
g
)
+
−
6
=
−
12
+
6
g
+
−
6
Combine Like Terms:
=
−
12
+
6
g
+
−
6
=
(
6
g
)
+
(
−
12
+
−
6
)
=
6
g
+
−
18
Answer:
=
6
g
−
18

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Select the correct answer. which expression is equivalent to the given expression? assume the denominator does not equal zero. a

Alexxandr [17]

If the denominator does not equal 0, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$ $\frac{x^{10} y^{14}}{729}$

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

$\frac{14x^4y^6}{7x^8y^2}$

Divide 14 by 7

$\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}$

Apply the law of indices

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}$

Evaluate the differences in the exponents

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}$

Hence, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$

Read more about equivalent expressions at:

brainly.com/question/2972832

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4 0

2 years ago

Which of the following expressions is equal to the expression 4x-2(3x-9)? 18-2x,-10x-18,-2x-18,10x-18

nordsb [41]

4x - 2(3x - 9)....distribute the 2 thru the parenthesis
4x - 6x + 18....combine like terms
-2x + 18 <===

8 0

3 years ago

he graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is

Reika [66]

Answer:

The answer is 2

Step-by-step explanation:

Rate of change of function is given by :

$\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}$

For function y = 6,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{6-6}{x_{2}-x_{1}}\\=0$

because the function is independent of x.

For function y = 2·x + 7,

rate of change =

$=\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}+7-2\cdot x_{1}-7}{x_{2}-x_{1}}\\=\frac{2\cdot x_{2}-2\cdot x_{1}}{x_{2}-x_{1}}\\=\frac{2\cdot (x_{2}-x_{1})}{x_{2}-x_{1}}\\=2$