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3 years ago

Help if you love the boiz

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

6 0

Answer:

I believe it's parrolelegram rectangle and square

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A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%

OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

Step :- (i)

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

95% of confidence intervals

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$

Step:-(ii)

The degrees of freedom γ=n-1 = 15-1=14

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

$(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )$

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

Conclusion:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0

3 years ago

Help plz no links unhelpful answers will get reported use formulas plz. I'm being gneerous

MA_775_DIABLO [31]

Answer:

what's the question?? I b.d ont get it

7 0

2 years ago

The bar graph in the following graphic represents fictional net exports in billions of dollars for five countries. Net exports a

harina [27]

Answer:

$80 billion

Step-by-step explanation:

From the graph, we have the following:

$United\ States = -110$

$Denmark = -30$

$China = 120$

$Germany = 40$

$Spain = 30$

Required

Determine the difference in US and Denmark exports

The difference is calculated as thus:

$Difference = Denmark - United\ States$

This gives:

$Difference = -30 - (-110)$

$Difference = -30 +110$

$Difference = 80$

Hence, the difference is $80 billion

8 0

2 years ago

Find the 6th term of the arthemetic sequence 2x+3,-2x+10,-6x+17,..

sveticcg [70]

Answer:4h term: -10x+24, 5th term: -14x+31, 6th term: -18x+ 38

Step-by-step explanation:

8 0

3 years ago

A study was conducted to determine whether there were significant differences between medical students admitted through special

Mekhanik [1.2K]

Answer:

$P(X\geq 9)=P(X=9)+P(X=10)$

And using the probability mass function we got:

$P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383$

$P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402$

And replacing we got:

$P(X \geq 9) = 0.383 +0.402= 0.785$

Step-by-step explanation:

Let X the random variable of interest "number of students graduated", on this case we now that:

$X \sim Binom(n=10, p=0.913)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We want to find the following probability:

$P(X\geq 9)=P(X=9)+P(X=10)$

And using the probability mass function we got:

$P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383$

$P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402$

And replacing we got:

$P(X \geq 9) = 0.383 +0.402= 0.785$

3 0

3 years ago