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Usimov [2.4K]
2 years ago
5

Help me out please ;v;

Mathematics
1 answer:
Musya8 [376]2 years ago
3 0
First you rewrite all the expressions like this:
8x+4=(2x+12)+(2x+4)

then you solve and get:
x=3

to solve for AC, you have to solve 8x+4 by replacing x with 3

8x+4 would be rewritten as:
8(3)+4

AC=28
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3 0
2 years ago
Ut 28, <br> –<br> 46, and 8 in order from least to greatest.
Stella [2.4K]

Answer:

-46, 8, 28

Step-by-step explanation:

5 0
3 years ago
If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term​
Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = a_{2} - a_{1} = a_{3} - a_{2}

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

a_{n} = a_{1} + (n - 1)d

a_{1} = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

a_{8} = 4 + (7 × 5) = 4 + 35 = 39

4 0
3 years ago
Plss help!<br>Question: Find a,b and c​
Roman55 [17]

Answer:

See below, please

Step-by-step explanation:

The right:

{(y + c)}^{2}  - b \times (x + a) \\  = ( {y}^{2}  + 2yc +  {c}^{2} ) - bx - ba  =

= {y}^{2}  - bx + 2cy +  {c}^{2}  - ab

The left:

=  {y}^{2}  - 7x - 18y + 109

So, after comparing the right side and the left side of this equation, we know

1)

b = 7

2)

2c =  - 18 \\ so \\ c =  - 9

3)

{c}^{2}  - ab = 109

So,

a =  \frac{ {c}^{2}  - 109}{b}  =  \frac{ { (- 9)}^{2}  - 109}{7}  =  \frac{ - 28}{7}  =  - 4

6 0
2 years ago
-5x + 4 = 2x + 16<br> How do I solve this
Cloud [144]
Subtract 2x from both sides then you’d have -7x+4=16 Then you subtract 4 from both sides and you’d get -7x=12. Next you divide both side by -7 so x=1.75 rounded to the nearest hundredth.
8 0
3 years ago
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