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Marat540 [252]
4 years ago
10

A car travels 240 miles in 4 hours. at this rate, how many miles will it travel in 8 hours

Mathematics
1 answer:
oksian1 [2.3K]4 years ago
8 0
First you need to find the rate. This problem is based on the formula d = rt
d = distance
r = rate 
t = time.

The question is asking how many miles will it travel in 8 hours so to find this out we need to find the rate when the car travels 240 miles in 4 hours. We use this information and plug it into the model d = rt

d = 240
r = don't know yet
t = 4 hr
d = rt 
240 = 4r
240 / 4 = 4r / 4
60 = r
r = 60
So the car is going at a rate of 60 miles per hour. Now that we know this we can solve for how many miles the car will travel in 8 hours.
d = rt
d = r * t
d = 60 * 8
d = 480

So the car will travel 480 miles in 8 hours

Another way to think about this is that you know the car traveled 240 miles in 4 hours and the question is wanting to know how far the car will travel in 8 hours, which would be double the 4 hours so 240 + 240 = 480

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Sandra has 46 fewer coins than Martha. Sandra has 57 coins . how many coins does Martha have?
hoa [83]
M = 57+46
(Since she has 46 less then martha, you know to find how many martha has you have to add 46!)

M=103

So martha has 103 coins!
6 0
3 years ago
I️ have to use 15 as Y
statuscvo [17]
-1/5of 15 =-3 then add 3 2/5th which is 17/2 so -3+17/2 = 11/2=5 1/2
7 0
3 years ago
John had $21 to spend on 2 notebooks. After buying them he had $13. How much did each notebook cost?
Eva8 [605]

john had 21.00After buying 2 notebooks he had 13.00

21-13= 8 / 2 =4 each notebook cost 4 dollars.

5 0
3 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
3 years ago
Demarcus and his brother are saving up some money to take a trip together. to open a joint savings account, demarcus deposited a
Anastaziya [24]

a. Demarcus' method is (d + d + 7) = 111/3

b. His brother's method is 3d + 3d + 3 × 7 = 111

c. The banker's method is 3(2d + 7) = 111

<h3>How to complete each person's method</h3>

Each pperson's method is the solution to a linear equation

<h3>What is a linear equation?</h3>

A linear equation is an equation in which the highest power of the unknown is 1.

<h3>a. How to complete Demarcus' method?</h3>

Since the equation is given by 3(d + d + 7) = 111 and demarcus was solving the equation and his first step was to divide both sides by 3, we have that

3(d + d + 7) = 111

(d + d + 7) = 111/3

d + d + 7 = 37

2d + 7 = 37

2d = 37 - 7

2d = 30

d = 30/2

d = 15

So, Demarcus' method is (d + d + 7) = 111/3

<h3>b. How to complete his brother's method?</h3>

Since the equation is given by 3(d + d + 7) = 111 and his brother started solving the equation by using the distributive property,we have that

3(d + d + 7) = 111

3d + 3d + 3 × 7 = 111

3d + 3d + 21 = 111

6d + 21 = 111

6d = 111 - 21

6d = 90

d = 90/6

d = 15

So, his brother's method is 3d + 3d + 3 × 7 = 111

<h3>c. How to complete the banker's method?</h3>

Since the equation is given by 3(d + d + 7) = 111 and their banker started solving the equation by combining like terms, we have that

3(d + d + 7) = 111

3(2d + 7) = 111

6d + 21 = 111

6d = 111 - 21

6d = 90

d = 90/6

d = 15

So, the banker's method is 3(2d + 7) = 111

Learn more about linear equation here:

brainly.com/question/26260688

#SPJ1

6 0
2 years ago
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